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Yuki888 [10]
2 years ago
13

​claim: the mean pulse rate​ (in beats per​ minute) of adult males is equal to 69 bpm. for a random sample of 140 adult​ males,

the mean pulse rate is 70.4 bpm and the standard deviation is 11.1 bpm. find the value of the test statistic.

Mathematics
1 answer:
zaharov [31]2 years ago
8 0

Answer:

93.19%

Step-by-step explanation:

We have that the mean (m) is equal to 70.4, the standard deviation (sd) 11.1 and the sample size (n) = 140

They ask us for P (x =69)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (69 - 70.4) / (11.1 / (140 ^ (1/2)))

z = 1.49

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <1.49) = 0.9319

The probability is 93.19%

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\cfrac{AU}{AB} =\cfrac{UV}{BC}    \\  \\  \cfrac{20x+108}{20x+381} =\cfrac{444}{703}   \\  \\ 703(20x+108)=444(20x+381)\\\\14060x+75924=8880x+169164 \\  \\ 14060x-8880x = 169164 - 75924 \\  \\ 5180x = 93240 \\  \\ x=93240/5180 \\  \\ x=18
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bagirrra123 [75]

Answer:

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Step-by-step explanation:

So basically we are modelling how much the coach is spending. Each player is given a uniform and a basketball

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