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Reptile [31]
1 year ago
5

FIRST TO ANSWER THIS QUESTION WILL BE MARKED AS BRAINLIEST AND ALSO I WILL FOLLOW THAT PERSON.

Mathematics
1 answer:
jonny [76]1 year ago
7 0

\huge\text{Hey there!}


\mathsf{\dfrac{625\times (3\times2)^3}{3^2\times10^2}}

\mathsf{= \dfrac{625\times(6)^3}{3^2\times10^2}}

\mathsf{= \dfrac{625\times(6^3)}{3^2\times10^2}}

\mathsf{= \dfrac{625\times6^3}{3^2\times10^2}}

\mathsf{= \dfrac{625\times216}{9\times100}}

\mathsf{= \dfrac{135,000}{900}}

\mathsf{= \dfrac{135,000\div900}{900\div900}}

\mathsf{= \dfrac{150}{1}}

\mathsf{= 150\div1}

\mathsf{= 150}


\huge\textsf{Therefore, your answer should be:}

\huge\boxed{\frak{150}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
~\frak{Amphitrite1040:)}</h3>
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3 years ago
The sum of two numbers is 53. if twice the first number minus three times the second number is 26, find both numbers.
EastWind [94]
Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53   (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a -  3b = 26
------------------- - (substract)
       5b = 80
         b = 80/5
         b = 16

Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
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The numbers are 16 and 37</span>
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m=76

Step-by-step explanation:

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