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3 years ago

What sentence about markdowns and markups is true?

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

The answer is C.
C. A markup has no limit, but a markdown is limited to 100% or less.

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Find the equation of a line containing the given points. Write the equation in slope-intercept form.

Alja [10]

X=2 because both coordinates have x as 2

4 0

3 years ago

Read 2 more answers

Original price: $64; Markup: 15% what is the retail price?

Brrunno [24]

Answer:

$73.60

Step-by-step explanation:

Original price: $64

Markup: 0.15($64) = $9.60

New retail price: $64 + $9.60 = $73.60

4 0

2 years ago

Find values of sine cosine tangent for

slava [35]

Answer:

The correct answer is option a

Sin A = 2√13/13

Cos A = 3√13/13

Tan A = 2/3

Step-by-step explanation:

From the figure we can see that,a right angled triangle.

ΔABC

To find side AB 

AB = √(AC)² + (BC)² =√(36² - 24² )= √1872

AC = 12√13

 To find the trigonometric ratio 

Sin A = BC/AB = 24/12√13 = 2√13/13

Cos A = AC/AB = 36/ 12√13 = 3√13/13

Tan A = BC/AC = 24/36 = 2/3

6 0

3 years ago

Read 2 more answers

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

Given:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

Value of x:

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

6 0

3 years ago

2x - y - 4 = 0 3x + y - 9 = 0 What is the solution set of the given system?

Ad libitum [116K]

Answer:

$(\frac{13}{5};\frac{6}{5}).$

Step-by-step explanation:

$1)\left \{ {{5x=13} \atop {y=2x-4}} \right. \ 2)\left \{ {{x=\frac{13}{5} } \atop {y=\frac{6}{5} }} \right.$

short explanation: 1) to add the 1st equation to the 2d; 2) to calculate the value of 'x', then to substitute x=13/5 into the 2d equation and calculate the value of 'y'.

5 0

2 years ago