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Lapatulllka [165]
4 years ago
9

3e≤6 a e=1 b e=2 c e=3

Mathematics
1 answer:
lesya [120]4 years ago
7 0
A and b are both accurate

For a:
3(1) \leqslant 6 = 3 \leqslant 6
which is true

For b:
3(2) \leqslant 6 = 6 \leqslant 6
which is also true
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1.11(5) - 11(4) =
Natali5045456 [20]

Answer:

1) 11

2) -8

3) 30

15) 80x - 128

16) 138y

Step-by-step explanation:

For these problems, you will need to use either PEMDAS or distributive property.

PEMDAS stands for parentheses, exponents, multiplication/division, addition/subtraction. Problems must be solved by going in order of the acronym, always starting with anything in parentheses first.

Example of PEMDAS:

2) 8(-3 + 2)

Solve for what's inside the parentheses first. There are no exponents, multiplication, or division within the parentheses so next would be addition and subtraction.

-3 + 2 = -1 so the problem will now look like:

8 (-1)

Next, PEMDAS says to look for exponents. There are none. Multiplication and division are next. 8 is being multiplied by -1 so lets try that:

8 × -1 = -8

-8

Distributive property is when you take the number being multiplied on the outside of the parentheses and multiply it to each individual number within the parentheses.

Example of distributive property:

2) 8(-3 + 2)

Multiply the number on the outside of the parentheses, 8, to each number within the parentheses, -3 and 2:

8 × -3 and 8 × 2

The problem should look like:

-24 + 16

Then solve:

-8

Use whichever method you are most comfortable with as both will produce the same answer. I will solve the first few and the last few to help you.

1)

11(5) - 11(4)

55 - 44

11

3)

6(9) - 4(6)

54 - 24

30

15) *You must use distributive property for these last problems as you cannot add or subtract numbers and variables*

16(5x - 8)

80x - 128

*You can only combine like terms so this is fully simplified*

16)

23y(2 + 4)

46y + 92y

138y

5 0
3 years ago
Whats 4(d+2)-2d=3(2+d)
Dmitry [639]

Simplify:

4(d + 2) - 2d = 3(2 + d)\\4d + 8 - 2d = 6 + 3d\\d + 8 - 2d = 6\\-d + 8 = 6\\-d = -2\\d = 2

d is equal to 2.

6 0
3 years ago
Find the final amount of money in an account if
LuckyWell [14K]

Answer:

10213.33

Step-by-step explanation:

use the formula to answer this question

principal=7,200

rate=0.06

compounded anually=1

time=6

Hope it helped..

3 0
3 years ago
PLZZZZZZ HELP I DON'T WANNA GET IT WRONG
prohojiy [21]

Answer:

She will save $5.25

Step-by-step explanation:

21 x 25% = 5.25

3 0
3 years ago
Read 2 more answers
Expand the equation (p+q)^5
VashaNatasha [74]
(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
7 0
3 years ago
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