False
true
false
i could be wrong but i’m 85% certain
Answer:
∠U = 56.4
Step-by-step explanation:
We can use trigonometric functions to solve this
Here we are given the opposite side of ∠U as well as the adjacent side.
When dealing with the adjacent and opposite side we use sin
Sin = Opposite side / Adjacent side
Opp = 5 and adj = 6
So
Sin(U) = 5/6
* take the inverse sine of both sides *
arc(sin)(u) = u
arcsin(5/6) = 56.4 *( rounded to the nearest tenth )
∠U = 56.4
You find the area of a triangle by using 1/2*b*h where b is the base and h is the height. since we already know the area is 20 and the height is for you plus them in so the problem would be 20= 1/2 (b) (4) then you multiply what you know together to get 20= 2b and then isolate the b by dividing both sides by two so the base should be 10 m
Hey
Question 1: For this one, we simply need to look at the "fat grams over 25" and the "Total" sections. We can see that 27 out of 50 have fat grams over 25. This written as a percentage is: 54%
Question 2: Using the same logic above we conclude the answer is 45.45%
Question 3: For this we need to look at the "total" section and the answer is 50
Question 4: We add all the "over 300" and write it as a percentage out of 50 which is 14%
Question 5: Same as #1 answer is 21%
Hope this helps
Answer:
option b)
tan²θ + 1 = sec²θ
Step-by-step explanation:
The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.
hypotenuse² = height² + base²
Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.
<h3>1)</h3>
sin²θ + 1 = cos²θ incorrect
<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>
by dividing first identity by cos²θ
sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ
<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>
1 - cot²θ = cosec²θ incorrect
by dividing first identity by sin²θ
sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ
<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>
1 - cos²θ = tan²θ
not such pythagorus identity exists
