Find the length of the missing side. a= 7, b= 6, c= x
2 answers:
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I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.
Answer:
2.99 x 10⁸ meters per second
Step-by-step explanation:
Scientific notation (also called "Standard form") is written in the form of , where
and
is any positive or negative whole number.
To <u>convert</u> a number into <u>scientific notation</u>, move the decimal point to the left or right until there is <u>one digit before the decimal point.</u>
The number of times you have moved the decimal point is the power of 10 ().
If the decimal point has moved to the <u>left</u>, the power is <u>positive</u>.
If the decimal point has moved to the <u>right</u>, the power is <u>negative</u>.
<u>To convert the given number to scientific notation</u>
The decimal point for the given number 299000000 is after the last zero:
⇒ 299000000.
Move the decimal point 8 places to the left:
⇒ 2.99000000
Get rid of the redundant zeros:
⇒ 2.99
Multiply by 10 to the power of the number of decimal places moved:
⇒ 2.99 x 10⁸
Therefore, the speed of light using scientific notation is:
- 2.99 x 10⁸ meters per second
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)