Answer:
188π in^2
Step-by-step explanation:
Surface area of the rocket = surface area of the cone + surface area of the cylinder
Surface area of a cone = πr(r+h^2+r^2)
r = 8/2 = 4 in
4π( 4 + 3^2 + 4^2) =
4π ( 4 + 9 + 16) = 116π in^2
Surface area of a cylinder = 2πrh+2πr^2
(2 x n x 4 x 5) + (2 x n x 16)= 72π in^2
116 + 72 = 188π in^2
Answer:
628/1300
Step-by-step explanation:
These are what would represent her problem..
Answer:
Step-by-step explanation:
tanx=27/38
take the inverse...
tan^-1(27/38)
≈35.4 degrees
1. 7 and -7 are both 7 units away from 0. They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.
2. 5 and -5 are both 5 units away from 0. They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.
3. 2 and -2 are both 2 units away from 0. They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.
Hope that helps
Answer:
2 relative maxima and minima
(2, 6.2) = maxima
(0, -4) = minima
*tell me if I got this wrong