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diamong [38]
3 years ago
12

An 'A' is considered 4.0, a 'B' is 3.0, a 'C' is 2.0, a 'D' is 1.0, and an 'F' is 0. If you received the following grades in you

r first semester, what would your grade point average be?
Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

2.2gpa

Step-by-step explanation:

you add the value if the letter grades up and divide by how many classes you have. for this case you have 5 and you would add 4+3+2+1+0=10/5=2.2

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Rose bought some spinach. She used 3/5 of the spinach on a pan of spinach pie for a party and 3/4 of the remaining spinach for a
SashulF [63]
a. She used 1/10 of the spinach for a salad.

b. She used 1/2 pound of spinach for the salad.

We can solve each part of this problem by using a "fraction strip". The strip helps show a breakdown of what portion of spinach was used for each the party, family, and salad. See the attached image for a step by step example of how to multiply the fractions to find the correct portions. 

4 0
3 years ago
Read 2 more answers
Which fraction is not equivalent to 9/12<br> 15/20<br> 24/32<br> 6/8<br> 16/24
s2008m [1.1K]

Answer:

16/24

Step-by-step explanation:

9/12–> simplify to 3/4

3/4=15/20

24/32=3/4

6/8=3/4

16/24 is not equal

6 0
2 years ago
Read 2 more answers
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
A pair of pant and a t-shirt cost $25. If the pant cost $7.28 more than the shirt, how much did the pant cost?
Lena [83]
$16.14 =pants

Explanation:

$25-$7.28=17.72

17.72/2 =8.86

8.86+7.28=16.14

25-16.14=8.86 shirt

I hope that helped ..
4 0
2 years ago
Read 2 more answers
Can any math genius help me with this
vovangra [49]

<em>Here's</em><em> </em><em>my</em><em> </em><em>working</em><em> </em><em>for</em><em> </em><em>1</em><em>)</em><em> </em><em>You</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>exterior</em><em> </em><em>angle</em><em>,</em><em> </em><em>then</em><em> </em><em>divide</em><em> </em><em>by</em><em> </em><em>360</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>sides</em><em>:</em>

<em>Applying</em><em> </em><em>these</em><em> </em><em>steps</em><em> </em><em>:</em><em> </em>

180 (Interior Angles) - 162 = 18 (Exterior angle)

360 ÷ 18 is<em> </em><em>20</em><em> </em><em>sides</em><em> </em>

<em>For</em><em> </em><em>2</em><em>)</em>

<em>Its</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>method</em><em>,</em><em> </em><em>so</em><em> </em><em>apply</em><em> </em><em>the</em><em> </em><em>steps</em><em>:</em>

<em>180</em><em> </em><em>-</em><em> </em><em>175</em><em> </em><em>=</em><em> </em><em>5</em>

<em>360</em><em> </em><em>÷</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>72</em><em> </em><em>sides</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em><em> </em><em>:</em><em>)</em><em> </em>

8 0
2 years ago
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