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diamong [38]
3 years ago
12

An 'A' is considered 4.0, a 'B' is 3.0, a 'C' is 2.0, a 'D' is 1.0, and an 'F' is 0. If you received the following grades in you

r first semester, what would your grade point average be?
Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

2.2gpa

Step-by-step explanation:

you add the value if the letter grades up and divide by how many classes you have. for this case you have 5 and you would add 4+3+2+1+0=10/5=2.2

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Find the median:<br> 3.8, 4.2, 4.0, 4.2, 4.2
Setler [38]

Answer:

4.2 is your median

Step-by-step explanation:

just o the math

7 0
2 years ago
Read 2 more answers
Clayton drove at a constant rate on the highway for a trip to the beach. He did not make any stops along the way. The distance C
Nikolay [14]

The answer is the first 1 !!

Here is how we see if it is true!

If Clayton drives 60 miles per hour, that means, <u>t</u>hat after one hour has passed, they should have traveled 60 miles!

If we look at the number of hours that have passed between 1:30 and 4:30, it is 3 hours.

If someone travels 60 miles every hour that has passed, and they traveled for 3 hours. To find how far they have traveled we just need to multiply 60 miles by 3 hours!

Let's solve that!

60 × 3 = 180 miles!

Clayton started driving at 1:30 pm and went 60 miles per hour.

3 0
2 years ago
3 tons 600 pounds=_____pounds
Anna11 [10]

3 tons + 600 lbs = 6600 lbs

4 0
3 years ago
Read 2 more answers
Simplify polynomial
Kay [80]

Answer:

j² - 5j²k - 2

Step-by-step explanation:

3j² - j²k - 6 - 4j²k - 2j² + 4

To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.

We have three groups of like terms:

The j-squares (j²), the j-squared k (j²k) and the constants (no variable).

Remember to include the negatives!

The j-squares are: 3j² ; -2j²

The j-squares k are: - j²k ; - 4j²k

The constants are: - 6 ; 4

Simplify:

3j² - j²k - 6 - 4j²k - 2j² + 4

Rearrange the polynomial by like terms

= (- j²k - 4j²k) +  (3j² - 2j²) + (- 6 + 4)

Add or subtract the like terms

= (-5j²k) + (j²) + (-2)

Remove brackets and rearrange so the negative is not first

= j² + - 5j²k + - 2

Simplify where two signs are together. Adding a negative is subtraction.

= j² - 5j²k - 2                  Simplified

8 0
3 years ago
A can in the shape of a cylinder has a diameter of 10 cm and a height of 6 cm. how much wrapping paper is needed to cover the cy
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

To determine the amount of wrapping paper needed to cover the can, we would determine the total surface area of the cylindrical can. The formula for determining the total surface area of a cylinder is expressed as

Total surface area = 2πr² + 2πrh

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Diameter = 10 cm

Radius = diameter/2 = 10/2

Radius = 5 cm

Height = 6 cm

Therefore,

Total surface area = (2 × 3.14 × 5²) + (2 × 3.14 × 5 × 6)

= 157 + 188.4 = 345.4 cm²

345 cm² of wrapping paper is needed to cover the cylinder.

2) Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

3 × Volume of cone = πr²h

The volume of the cylinder is 3 times greater than the volume of the cone. Therefore, the volume of the cone is 1/3 times lesser than the volume if the cylinder.

5 0
3 years ago
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