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erica [24]
3 years ago
9

I need to know the answer ASAP

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0

Answer:

A

Step-by-step explanation:

The numerical coefficient is sqrt(8/3), so all you have eliminated is D.

Now you have to consider the literal all by itself.

sqrt(x^2)/sqrt(x) can be written as (sqrt(x^2/x)) = sqrt(x)

x^2 when divided by x leaves x

another way of looking at it is sqrt(x)*sqrt(x) / sqrt(x) = sqrt(x)

So the answer is sqrt(8/3 * x)

Andrej [43]3 years ago
3 0

Answer:

Step-by-step explanation:

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3(r-1) -2(r+3) =0 anybody know the answer to that ?
agasfer [191]

Answer:

r = 9

Step-by-step explanation:

3(r - 1) - 2(r + 3) = 0

First, use the distributive property.

3r - 3 -2r - 6 = 0

Now, isolate the variable "r" to one side by adding the opposite of the whole numbers to each side so it cancels it out on the left ide and adds it to the right.

3r - 3 -2r - 6 = 0

   +3        +6    +3 +6

3r - 2r = 9

Subtract the r's.

r = 9

Now that we know r = 9, we can plug in 9 into the original (but distributed) expression for every time it uses the variable "r" to check our work.

3r - 3 -2r - 6 = 0

3(9) - 3 - 2(9) - 6 = 0

27 - 3 - 18 - 6 = 0

24 - 24 = 0

0 = 0

So, r = 9 is true.

Hope this helps! If you have any additional questions, please don't hesitate to ask me or your teacher to be sure you master the subject. Stay safe, and please mark brainliest!

6 0
2 years ago
Find the value of x. Explain your work please.<br>Concurrency of Angle Bisectors
vovangra [49]

Answer:

x+5=2x-1

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Consider the following theorem and proof.Theorem: The number âš2 is not rational number.Proof: Let's suppose âš2 is a rational n
ololo11 [35]

Answer:

The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

Step-by-step explanation:

We need to  show that the √2 is an irrational number.

And from the given steps of proof stated in the question, we need to find the assumption that justifies the fact : " Both of the number a and b cannot be even".

First take the given options :

Option a : √2 is a rational number

√2 being an rational or irrational has no relation of a and b to be even or odd. So, this option is rejected.

Option B : a/b is simplified lowest terms

This shows that a and b are not even because if a and b are even then a/b can be simplified in other lowest term.

Option c : √2 is a irrational number

Similarly, By using the inverse part of Option A, option c is also rejected.

Option d : The fact that b divides a evenly

This only shows that the a is even. This does not give any idea about b is even or not. So option D is also rejected.

Option E : The fact that a and b are whole numbers

This fact does not imply that the a and b are even or odd. So option E is also rejected.

Hence, The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

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