Question

Pablo’s Gourmet Pretzel Shop specializes in selling the very finest chocolate covered pretzels. Rico bought 4 white chocolate pretzels and 6 dark chocolate pretzels for $10.50. Holden bought 8 white chocolate and 3 dark chocolate pretzels for $9.75. Determine the total cost for 6 white chocolate pretzels and one dark chocolate pretzel.

Answer 1

The total cost of 6 white chocolate pretzels and one dark chocolate pretzel is $5.75

Step-by-step explanation:

Let,

Cost of one white chocolate pretzel = x

Cost of one dark chocolate pretzel = y

According to given statement;

4x+6y=$10.50      Eqn 1

8x+3y=$9.75        Eqn 2

Multiplying Eqn 1 by 2

$2(4x+6y= 10.50 )\\8x+12y=21\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(8x+12y)-(8x+3y)=21-9.75\\8x+12y-8x-3y=11.25\\9y=11.25$

Dividing both sides by 9

$\frac{9y}{9}=\frac{11.25}{9}\\y=1.25$

Putting y=1.25 in Eqn 1

$4x+6(1.25)=10.50\\4x+7.50=10.50\\4x=10.50-7.50\\4x=3$

Dividing both sides by 4

$\frac{4x}{4}=\frac{3}{4}\\x=0.75$

Cost of 6 white chocolate pretzels and one dark chocolate pretzel = 6x+y

Cost of 6 white chocolate pretzels and one dark chocolate pretzel = 6(0.75)+1.25 = $5.75

The total cost of 6 white chocolate pretzels and one dark chocolate pretzel is $5.75

Keywords: linear equation, elimination method

Learn more about linear equations at:

• brainly.com/question/9381080
• brainly.com/question/9532142

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