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Paladinen [302]
3 years ago
15

Jimmy wants to buy 4 pounds of potatoes, but the supermarket only sells potatoes as kilograms. how many kilograms of potatoes sh

ould Jimmy buy?
(pounds= 1 kilogram)
Mathematics
1 answer:
BARSIC [14]3 years ago
4 0
It will have to be about 1.814 kilograms
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Please help it’s due tonight. Your help will be greatly appreciated.There is also a graph. WILL PUT YOU AS BRAINLY!!!!!!
chubhunter [2.5K]

Answer: see below

Step-by-step explanation:

The shape is a trapezoid

Base 1 (BH) is 10

Base 2 (QA) is 14

Height is 5

Area

A=\frac{base_{1} +base_{2} }{2} h

A=\frac{10+14}{2} *5\\A=12*5\\A=60

Find distance between QB and HA

D=\sqrt{(x_{2} -x_{1}) ^{2}+(y_{2}-y_{1})  ^{2}

Q( -4,4)  B (-2,9)

D=\sqrt{(-2--4)^{2}+(9-4)^{2}  } \\D=\sqrt{2^{2} +5^{2} } \\D=\sqrt{29}

Perimeter

P=10+14+2\sqrt{29} \\P=24 +2\sqrt{29} \\P= 24+10.77\\P=34.77

5 0
3 years ago
Find the area of the figure
faust18 [17]
Hshsdusisidjdjfjejdixhdbsisoxnd she
6 0
3 years ago
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
Write an equation of the line that passes through the points (-2,-2) and (0,5)
marshall27 [118]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&&(~ -2 &,& -2~) 
&&(~ 0 &,& 5~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-2)}{0-(-2)}\implies \cfrac{5+2}{0+2}\implies \cfrac{7}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=\cfrac{7}{2}[x-(-2)]
\\\\\\
y+2=\cfrac{7}{2}(x+2)\implies y+2=\cfrac{7}{2}x+7\implies y=\cfrac{7}{2}x+5
3 0
3 years ago
I need help with 6,7 pleaaseee
antiseptic1488 [7]
6. addition property of equality (because 7 was added to each side)

7. A function has no repeating x values.....so the one that is not a function WILL HAVE repeating x values......and that would be C because it has repeating 2's
5 0
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