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Paladinen [302]

3 years ago

15

Jimmy wants to buy 4 pounds of potatoes, but the supermarket only sells potatoes as kilograms. how many kilograms of potatoes sh

ould Jimmy buy?
(pounds= 1 kilogram)

1 answer:

BARSIC [14]3 years ago

4 0

It will have to be about 1.814 kilograms

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Jerry bought toy trains at the store. He gave 15 away and had 9 left. Which of the following shows how

Paladinen [302]

The answer of this question is<u> 24 toy trains.</u>

<u>Step-by-step explanation:</u>

Given,

Jerry gave away 15 trains .

Jerry left with 9 trains .

Jerry total brought toy trains = given away toy trains + left with toy trains

Total toy trains = 15 + 9

Total toy trains = 24

<u>Jerry brought a total of 24 toy trains.</u>

7 0

3 years ago

Please will give brainliest!

vivado [14]

All of the statements except the first are true whether p ║ q or not.

The appropriate choice is ...

... ∠2 ≅ ∠6

_____

The "corresponding angles postulate" tells you that the lines are parallel if the corresponding angles are equal.

5 0

3 years ago

Read 2 more answers

Please help , thank you !!!!!!1

Lynna [10]

Answer is 7.
55+5X=90
5X=90-55
5X=35
X=35/5
X=7

6 0

2 years ago

What is the correct answer?

Valentin [98]

Answer:

Square Root of 384

Step-by-step explanation:

8 0

3 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

2 years ago