your final answer should be.... -3 • (61c - 70)
On the graph, we can see that when x=1, y=0.
But we don't even need to bother opening the attachment
and studying the graph !
In your question, you said that one point on the function is (1, 0) .
That means that when 'x' is 1, 'y' is zero. And there you are !
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
Answer:
d = -8
Step-by-step explanation:
Isolate the variable, d. Note the equal sign, what you do to one side, you do to the other. Divide -4 from both sides of the equation:
d = -8 is your answer.
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Answer:
1/4x (8 x - 15)
Step-by-step explanation:
write the division as a fraction
1/2x + 3/2x (x - 5 ÷ 2)
factor out 1/2 from the expression.
1/2x(x + 3(x - 5 ÷ 2))
divide the numbers.
1/2x(x + 3(x - 2.5))
distribute 3 through the parentheses.
1/2x(x + 3x - 7.5)
collect like terms.
1/2x(4x - 7.5)
1/2x(4x - 15/2)
factor out 1/2 from the expression.
1/2 x 1/2 x (8 x - 15)
multiply the fractions
= 1/4 x (8x - 15)
or alternative form
= 0.25(8x - 15)
