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ladessa [460]
4 years ago
5

For what ordered pair (a,b) are there infinite solutions (x,y) to the system ; 3ax + 3y=5b, 2x+y=5

Mathematics
2 answers:
Semmy [17]4 years ago
6 0

Answer:

The ordered pair is (2,3)

Step-by-step explanation:

we know that

If a system of equations has infinite solutions, then the equations are the same

we have

3ax+3y=5b -----> equation A

2x+y=5 ----> equation B

Multiply equation B by 3 both sides

3*(2x+y)=5*3

6x+3y=15 -----> equation C

Compare equation A and equation C

so

3ax=6x------> 3a=6 -----> a=2

5b=15 ------> b=3

The ordered pair is (2,3)

Oksana_A [137]4 years ago
3 0

Answer:

(2,3)

Step-by-step explanation:

For there to be infinite solutions, the first equation needs to be consistent with the second and yet add no new information, which means it must be a multiple of the second. Since the coefficient of y in the first equation is three times that of y in the second equation, the multiplier is 3. This implies that the first equation must be 3(2x+y)=3(5). After equating coefficients, this gives 3a=3×2 and $5b=3×5, or (a,b)=(2,3).

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