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Igoryamba
3 years ago
13

Paul and Tom both commute to work. Paul's commute on the train takes 15 minutes more than one third as many minutes as Tom's com

mute by car. It takes Paul 45 minutes to get to work. Write an equation to determine how many minutes it takes Tom to get to work.
45 = one thirdx − 15
45 = one thirdx + 15
45 = 3x − 15
45 = 3x + 15
Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

  45 = (one third)x + 15

Step-by-step explanation:

If x represents the number of minutes Tom commutes, then (1/3)x is "one-third as many minutes as Tom's commute." 15 minutes more than that is ...

  (1/3)x + 15

We are told this is the length of Paul's commute, and that it is 45 minutes. So, the appropriate equation is ...

  45 = (1/3)x +15

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5.) What is the GCF of the following<br> 6x2 and 12x3
algol13
Answer: 12
6x2 is 12 and 12x3 is 38.
We will first find the prime factorization of 12 and 36. After we will calculate the factors of 12 and 36 and find the biggest common factor number .

3 0
3 years ago
In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the
ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0
3 years ago
I need answer for this question
just olya [345]

The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.

In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:

Z = X-ц / σ

· It measures how many standard deviations the measure is from the mean.

· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ

σ = σ / \sqrt{n}    

σ is standard deviation

n is the sample size.

Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.

⇒ ц = 176.1  and σ = 35.4

For a sample of 43 passengers, we have

n = 43

σ =  \frac{35.4}{\sqrt{43}}

σ = 5.398

Z = X-ц / σ

Z = \frac{165-176.1}{5.398}

Z = -2.05 has p- value of 0.9798

The probability that the aircraft is loaded is

1 - p-value of Z

1 - 0.0202 = 0.9798

The probability that the aircraft is overloaded is 97.98%

Know more about Normal probability Distribution: -brainly.com/question/9333901

#SPJ9

6 0
1 year ago
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