All categories

3 years ago

PLEASE PLEASE PLEASE HELP!!!!!

Mathematics

1 answer:

Sveta_85 [38]3 years ago

4 0

I believe it would be a SAS

You might be interested in

a jogger is running around a 3/4 mile track and is 2/3 around the track. How far has the jogger traveled?

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

3/4 of a mi is equal to 0.75 mi

2/3 of .75 is .5

8 0

3 years ago

Read 2 more answers

What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°

IceJOKER [234]

Answer:

16.75 square cm

Step-by-step explanation:

$Area \: of \: sector = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{30 \degree}{360 \degree} \times 3.14 \times {8}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 64 \\ \\ = \frac{1}{3} \times 3.14 \times 16 \\ \\ = \frac{1}{3} \times 50.24 \\ \\ = 16.7466667 \\ \\Area \: of \: sector = 16.75 \: {cm}^{2}$

3 0

3 years ago

HELP PLEASE GIVING BRAINLIST TO ANYONE WHO ANSWERS

stira [4]

Answer:

7.5

Step-by-step explanation:

SInce 11x-17 is a corrosponding angle to 65, we can make an equation with them.

11x-17=65

Carry over the 17 (add to both sides)

11x= 82

divide 82 by 11

x=7.5

(the answer kept repeating so i rounded it to the nearest tenth)

Hope this helps :)

5 0

2 years ago

PLEASE HELP Due today!

AlexFokin [52]

Answer:

it looks like it is Addition Property Of Equality

Step-by-step explanation:

7 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago