OFFER A is cheaper.
Step-by-step explanation:
Given,
OFFER A
Pack of 5
£2.75
Pay for 3 packs get 1 free
And
OFFER A
Pack of 5
£2.75
Pay for 3 packs get 1 free
To find which offer is cheaper.
<u>For OFFER A</u>
For 4 Packets he needs to pay £2.75
He needs to buy 40 batteries.
He needs to buy 40÷(4×5) = 2 packets.
Total cost = £2.75
×2 = £5.5
<u>For OFFER B</u>
For 4 Packets he needs to pay £2.52
He needs to buy 40 batteries.
He needs to buy 10 packets.
After discount he has to pay = £2.52
-(£2.52
×
) = £1.68
Total cost = £1.68×10 = £16.8
Hence,
OFFER A is cheaper.
Split the second term in 6x^2 + 17x + 5 into two terms
6x^2 + 15x + 2x + 5 = 0
Factor out common terms in the first two terms, then in the last two terms.
3x(2x + 5) + (2x + 5) = 0
Factor out the common term 2x + 5
(2x + 5)(3x + 1) = 0
Solve for x
<u>x = -5/2, -1/3</u>