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harina [27]
3 years ago
15

Katelynn is saving her money to buy a new bike. Bikes that she likes start at $475. If she already has saved $285, what is the l

east amount she must save?
Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

190

Step-by-step explanation:

subtract 285 from 475

Keith_Richards [23]3 years ago
4 0
The least amount she must save is $190

work: 475-285 =190
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At Stephanie's new job, she spent $6.50, $8, $7.25, $13.50, and $9.75 on lunch the first week. In the second week, Stephanie spe
MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

sum1 = 45

Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

6 0
3 years ago
The area of the triangle below is 8.91 square inches. What is the length of the base?
Studentka2010 [4]

Answer:

8.1 inches

Step-by-step explanation:

Area of a triangle = ½ × base × height = Area

Rearranged =

\frac{area}{ \frac{1}{2}  \times height}

Base is the length by the way.

\frac{8.91}{ \frac{1}{2} \times 2.2 }

=8.1 inches

6 0
3 years ago
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There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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