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3 years ago

What is the slope of the line passing through the points (-3, 4) and (2, - 1)?

Mathematics

2 answers:

dimaraw [331]3 years ago

6 0

Answer:

slope = -1 or -x

Step-by-step explanation:

Do y2-y1/x2-x1

Plug in

-1 - 4/ 2 - -3 = -5/5

(Simplify)

-1 so the slope is

-1 or -x

If you want to find the equation use one of the points you have.

4 = -1(-3) + b

4 = 3 + b (subtract 3 on each side)

1 = b

y = -1x + 1 is the equation

Lubov Fominskaja [6]3 years ago

6 0

Slope = - 1

explanation:
m = y2 - y1
————
x2 - x 1

(x1,y1) = (-3,4) -1 - 4 -5
———————. -> ———- = ——- = -1
(x2,y2) = (2,-1). 2 - ( -3) 5

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What is the slope of the line that passes through the points (-7, -7) and (-7, 1) ?

ICE Princess25 [194]

Answer:

undefined

Step-by-step explanation:

(-7, -7) and (-7, 1)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(1 - (-7)) / (-7 - (-7))

Simplify the parentheses.

= (1 + 7) / (-7 + 7)

Simplify the fraction.

8/0

= undefined

Our line is a vertical line, which has an undefined slope.

Hope this helps!

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3 years ago

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irga5000 [103]

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6 0

3 years ago

Bob is trying to decide between two cell phone plans. Plan A has no flat fee, but the user must pay $10 cents per minute on the

professor190 [17]

$ per min is a rate. you multiple by minutes to get dollars.

A = 10x
B = 5x + 20

set them equal to find minutes, x.

10x = 5x + 20
10x - 5x = 20
5x = 20

x = 4

4 0

3 years ago

Read 2 more answers

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cestrela7 [59]

Answer:

f(x)=x^2+1 -> f(a+1)=(a+1)^2+1=a^2+2a+1+1=a^2+2a+2

Step-by-step explanation:

7 0

3 years ago

The graph of a line passes through the points (0, -2) and (6.0). What is

9966 [12]

Answer:

$y=\frac{1}{3}x-2$

Step-by-step explanation:

The equation of a line is given in the form $y=mx+b$

Where

m is the slope with formula $m=\frac{y_2-y_1}{x_2-x_1}$

and

b is the y-intercept [y axis cutting point of line]

Given the two points (0, -2) and (6,0),

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Now, we find m using formula:

$m=\frac{0+2}{6-0}=\frac{1}{3}$

Now we have

$y=\frac{1}{3}x+b$

Finding b, we plug in any (x,y) point. Lets put (6,0) and find b:

$y=\frac{1}{3}x+b\\0=\frac{1}{3}(6)+b\\0=2+b\\b=-2$

Thus,

equation of line = $y=\frac{1}{3}x-2$

5 0

3 years ago