The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
s = (1/2)√(a²+b²)
Answer:
4 square root 80^x
Step-by-step explanation:
2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
2(m² + 3n³)(m² - 3n³)
Answer:
x = -6
Step-by-step explanation:
-1.5x = 9 Divide the -1.5 on both sides
x = -6
Plug in the answer to make sure it works.
-1.5(6) = 9
9 = 9