Question not well presented
Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS
Answer:
The numerical length of RS is 22
Step-by-step explanation:
Given that
RS = 4x − 10
ST=2x−10
RT=4x−4
From the question above:
Point S lies on |RT|
So, RT = RS + ST
Substitute values for each in the above equation to solve for x
4x - 4 = 4x - 10 + 2x - 10 --- collect like terms
4x - 4 = 4x + 2x - 10 - 10
4x - 4 = 6x - 20--- collect like terms
6x - 4x = 20 - 4
2x = 16 --- divide through by 2
2x/2 = 16/2
x = 8
Since, RS = 4x − 10
RS = 4*8 - 10
RS = 32 - 10
RS = 22
Hence, the numerical length of RS is calculated as 22
Answer:
32.625 m
Step-by-step explanation:
You have the proportion ...
18 cm : ___ m = 22.4 cm : 40.6 m
This can be rearranged to ...
___ m/(18 cm) = (40.6 m)/(22.4 cm)
Multiplying by 18 cm gives ...
___ m = (40.6 m)·(18/22.4)
___ m = 32.625 m
The answer is C. If you substitute x for 6 and , the equation looks like this:
2(1+6)>5+8
Solve.
2(7)>13
14>13
Since 14 is greater than 13, the values make the statement true
Rule 1: Multiply by 2 then add 1 starting
( n x 2 +1) => 2n + 1
n is the position of our terms, so I substitute 1 because you're told to start from 1 which becomes our first term
2n + 1
2 x 1 + 1 =3
2 x 2 + 1 = 5
2 x 3 + 1 = 7
2 x 4 + 1 = 9
3,5,7,9....
(you can clearly see the sequence increasing by 2 each time, not following Multiply by 2 then add 1)
However, if we were to do add one each time, you'll add one to your pervious answer. So, this time I'll substitute the pervious answer
2 x 1 + 1 =3
2 x 3 + 1 = 7
2 x 7 + 1 = 15
2 x 15 + 1 = 31
3,7,15,31....
(from 3 to 7, you clearly see its multiplied by 2, then +1 & that's our sequence, this method apply to the second rule too of using previous)
Rule 2: Divide by 2 then add 4
(n ÷ 2 + 4) => n/2 + 4
n/2 + 4
(starting from 40.)
40/2 + 4 = 24
24/2 + 4 = 16
16/2 + 4 = 12
12/2 + 4 = 10
24,16,12,10.....
Answer: (started off with the number it asked of)
R 1 -
1,3,7,15,31....
(1 x 2 +1 does give 3)
R 2 -
40, 24,16,12,10.....
(40÷2 = 20, then + 4, gives 24)
Hope this helps!
N 4
Part A
a) 7a+2a+3b-------> (7a+2a)+3b-----> 9a+3b
b) 8p+2p-7q-------> (8p+2p)-7q------> 10p-7q
c) 9a²+2a²+5a-----> (9a²+2a²)+5a---> 11a²+5a
d) 5ab+2ab-7a-----> (5ab+2ab)-7a---> 7ab-7a
e) 7+2a-a------> 7+(2a-a)-----> 7+a
f) 2a+3b+5a+2b---> (2a+5a)+(3b+2b)-----> 7a+5b
g) 6p+2q-4p+4q---> (6p-4p)+(2q+4q)----> 2p+6q
h) 9m²+7m²+5m-3m-----> (9m²+7m²)+(5m-3m)------> 16m²+2m
i) 7a²+4a-2a²+7----> (7a²-2a²)+4a+7------> 5a²+4a+7
j) 10p-3q+p-7p-----> (10p+p-7p)-3q------> 4p-3q
k) 3x²+2x-2x²+3x+x²---> (3x²-2x²+x²)+(2x+3x)-------> 2x²+5x
N 5
a) If Julie buys 4 boxes and Michelle buys 7 boxes
in total
(4+7)*n-----> 7*n
the answer Part 5 a) is 7*n
b) (5kg+3kg)*b---------> 8*b
the answer Part 5 b) is 8*b
c) (3+4+6)*x-------> 13*x
the answer Part 5 c) is 13*x
N 6
a) L+B+L+B------> (L+L)+(B+B)-----> 2*L+2*B-----> 2*(L+B)
b)
1) L+L+L-----> 3*L
2) 5+5+5+5-----> 5*4
3) x+x+y-----> 2*x+y
4) a+b+c+c----> a+b+2*c
N 7
a) s+s+s+s+s+s+s+s------> 8*s
b) t+t+t+t-----> 4*t
c) t+t+t+t+t+t----> 6*t
d) t+t+t+s+s----> 3*t+2*s
e) t+t+t+s+s+s----> 3*t+3*s
f) 12*t+6*s
g) 10 squares+12 triangles-----> 10*s+12*t
h) n squares+m triangles-----> n*s+m*t
