How to find the side of a rhombus with given diagonals?
1 answer:
You might be interested in
Two numbers that add up to -19 and multiply to 48 are -16 and -3:
So, the solutions come from each parentheses: x+4=0, x-4=0, and x^2-3=0.
x+4=0
x = -4
x-4=0
x = 4
x^2-3=0
x^2 = 3
x = +/- √3
So, the solutions are -4, -√3, √3, and 4.
So, the solutions come from each parentheses: x+4=0, x-4=0, and x^2-3=0.
x+4=0
x = -4
x-4=0
x = 4
x^2-3=0
x^2 = 3
x = +/- √3
So, the solutions are -4, -√3, √3, and 4.
Answer:
I think that's right. I checked my answer and proved it on that sheet.
