Answer:
c
Step-by-step explanation:
hope it helps[]~( ̄▽ ̄)~*
Answer:
rhombus
Step-by-step explanation:
Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,
Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,
Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,
Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,
Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Note that the side adjacent to angle XYZ is given (6 cm) and that the hypo is also given (15 cm). Thus, cos XYZ = adj / hyp = 6 cm / 15 cm = 2/5 = 0.4.
XYZ is then arc cos 0.4. Use the arccos function on your calculator to determine XYZ and give XYZ in both degrees and radians.
Answer:
Step-by-step explanation:
<em>The question has missing options ; However, the question is still solvable</em>
Given
Direction = 2 units left
Required
Shift the function by 2 units in the x axis
The general format of shifting a function along the x axis (by the left) is as follows
Where c represents the direction;
Since , then