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il63 [147K]
2 years ago
12

Distance between A(2,7) and B(6,4)

Mathematics
2 answers:
r-ruslan [8.4K]2 years ago
4 0

Answer:

Approx: 2.65units

Step-by-step explanation:

ANTONII [103]2 years ago
4 0

Answer:

5

Step-by-step explanation:

d=\sqrt{(6-2)^{2}+(4-7)^{2}  } \\d=\sqrt{4^{2}+(-3)^{2}  } \\d=\sqrt{16+9} \\d=\sqrt{25} \\d=5

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Solve the given equation
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Eliminate the fractions by multiplying by least common multiple.
4,9,12 all go into 36 evenly. Multiply entire equation by 36.

36/4 = 9
36/9 = 4
36/12 = 3

New equation looks like:
9(w-1) +4(w+1) = -3(w+1) \\  \\ 9w -9 +4w +4 = -3w -3  \\  \\ 9w +4w+3w = -3 +9 -4 \\  \\ 16w = 2 \\  \\ w = \frac{2}{16} = \frac{1}{8}
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Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t
Amanda [17]

Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

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What is 20(21+68)-100+6
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Step-by-step explanation:

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