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GaryK [48]
2 years ago
6

A 40-kilogram bag of seed is spread evenly about the entire yard. How much, in kilograms, of the seed will NOT be watered? Use:

Percentage = watered squares / Total # of Square X 100
Mathematics
1 answer:
kvv77 [185]2 years ago
4 0

The computation of the percentage shows that the kilograms of seed that won't be watered is 12 kilograms.

<h3>How to calculate the percentage?</h3>

Your information is incomplete. Therefore an overview will be given. Let's assume that the watered squares are 35 while the total squares are 50.

Then, the percentage of the watered squares will be:

= 35/50 × 100

= 70%

Therefore, the percentage of the unwatered squares will be:

= 100% - 70%

= 30%

Then, the kilograms of the seed that won't be watered will be:

= Percentage of unwatered seed × Entire kilograms of seed

= 30% × 40kg

= 12kg

In conclusion, the seed that won't be watered is 12 kg.

Learn more about percentages on:

brainly.com/question/24877689

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see explanation

Step-by-step explanation:

Since a hexagon has 6 interior angles and the measure of one is 120°, then

sum of interior angles = 6 × 120° = 720°

exterior angle = 180° - interior angle = 180° - 120° = 60°



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Step-by-step explanation:

\frac{3}{4} x \frac{8}{3} =2

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At 10 A.M. a plane leaves Boston, Massachusetts, for Seattle, Washington, a distance of 3000 mi. One hour later a plane leaves S
Reil [10]

Answer:

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

Step-by-step explanation:

Plane-1 = Boston, Massachusetts - Seattle, Washington at 10:00 AM

Plane-2= Seattle, Washington - Boston, Massachusetts at 11:00 AM

Speed of plane-1 = 300 mile/hour

Distance covered by plane-1 in 1 hour = 300 mile/h × 1 h = 300 mile

Distance between plane-1 and plane 2 after 1 hour :

= 3000 mile - 300 mile = 2700 mile

Let the distance covered by plane-1 after 1 hour be x in t time where it will pass plane-2.

Let the distance covered by plane-2 be y in t time where it will pass plane-1.

x + y = 2700 ...[1]

Speed of plane-1 = 300 mile/hour

300 mile/h=\frac{x}{t}..[2]

Speed of plane-2 = 300 mile/hour

300 mile/h=\frac{y}{t}..[3]

Putting value of t from [2] in [3];

t=\frac{x}{300 mile/h}

300 mile/h=\frac{y}{\frac{x}{300 mile/h}}

\frac{x}{300 mile/h}=\frac{y}{300 mile/h}

x = y

In [1] put x = y

y + y = 2700 miles

2y = 2700 miles

y = 1,350 mile

For the value of t, put the value of y in [3]:

t=\frac{1,350 mile}{300 mile/h}=4.5 hour

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

5 0
3 years ago
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