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Leno4ka [110]
4 years ago
8

Assume that the weights of all packages of a certain brand of cookies are normally distributed with a mean of 32 ounces and a st

andard deviation of 0.3 ounce. find the probability that the mean weight, x¯, of a random sample of 20 packages of this brand of cookies will be between 31.8 and 31.9 ounces.

Mathematics
1 answer:
Anestetic [448]4 years ago
6 0
That probability is about 6.7%.

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Five years after 650 high school seniors graduated, 400 had a college degree and 310 were married. Half of the students with a c
DedPeter [7]

Answer:

The probability that a student has a college degree or is not married is 0.8308.

Step-by-step explanation:

The information provided is:

Total number of high school seniors (<em>N</em>) = 650.

Number of seniors with a college degree (<em>n</em> (C)) = 400.

Number of seniors who were married, (<em>n</em> (M)) = 310.

Consider the Venn diagram below.

The probability of an event, say E, is the ratio of the favorable outcomes of <em>E</em> to the total number of outcomes of the experiment.

That is,

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes of <em>E</em>

N = total number of outcomes of the experiment.

The probability of the union of two events is:

P(A\cup B)=P(A)+P(B)-P(A\cap B)=\frac{n(A)+n(B)-n(A\cap B)}{N}

Compute the probability that a student has a college degree or is not married as follows:

P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}

From the Venn diagram:

n (C) = 400

n (M^{c}) = N - n (M) = 650 - 310 = 340

n (C ∩ M^{c}) = 200

The value of P (C ∪ M^{c}) is:

P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}=\frac{400+340-200}{650}=0.83077\approx0.8308

Thus, the probability that a student has a college degree or is not married is 0.8308.

6 0
3 years ago
Read 2 more answers
А support wire 12 yards long is attached to the top of a utility pole 10
stira [4]

Answer:

6.6 yd

Step-by-step explanation:

a^{2}+b^{2}=c^{2}

10^{2}+b^{2}=12^{2}        Substitute a= 10 and c=12

100+b^{2}=144      Evaluate the Powers

b^{2}=44               Subtract 100 on both sides.

b=\sqrt{44}             Square root both sides b>0 so you dont need ⊥

b=6.6              Use a calculator to evaluate.

6 0
3 years ago
Find the general solution of <img src="https://tex.z-dn.net/?f=2cos%282x%20%2B%20%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%29%20%3D%20%5Cs
Aleks04 [339]

Answer:

\large\boxed{x=-\dfrac{\pi}{4}+k\pi\ \text{or}\ x=k\pi\ \text{for}\ k\in\mathbb{Z}}

Step-by-step explanation:

2\cos\left(2x+\dfrac{\pi}{4}\right)=\sqrt2\qquad\text{divide both sides by 2}\\\\\cos\left(2x+\dfrac{\pi}{4}\right)=\dfrac{\sqrt2}{2}\to2x+\dfrac{\pi}{4}=\pm\dfrac{\pi}{4}+2k\pi\\\\2x+\dfrac{\pi}{4}=-\dfrac{\pi}{4}+2k\pi\ \vee\ 2x+\dfrac{\pi}{4}=\dfrac{\pi}{4}+2k\pi\qquad\text{subtract}\ \dfrac{\pi}{4}\ \text{from all sides}\\\\2x=-\dfrac{2\pi}{4}+2k\pi\ \vee\ 2x=2k\pi\qquad\text{divide all sides by 2}\\\\x=-\dfrac{\pi}{4}+k\pi\ \vee\ x=k\pi\ \text{for}\ k\in\mathbb{Z}

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4 years ago
If you vertically compress the absolute value parent function, (x) = |X|, by a
dezoksy [38]

pls mark me as brainlist

thanks a lot

3 0
3 years ago
A jewelry artist is selling necklaces at an art fair. It costs $105 to rent a booth at the fair. The cost of materials for each
Over [174]

Answer:

1.35

Step-by-step explanation:

4 0
3 years ago
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