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3 years ago

Plz Answer In your own words Explain what the vertical line test is and how it is used.

Mathematics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer:

See below (I hope this helps!)

Step-by-step explanation:

The vertical line test is a test used to determine whether a relation is also a function. It is done by inserting several vertical lines that intersect the relation. If a vertical line intersects the relation at multiple point, then it is not a function. If every single inserted vertical line intersects the relation at only one point, then the relation is a function.

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Fourth degree and a single zero of -3

Darya [45]

The degree of a polynomial is the highest power of the polynomial.

The polynomial is $\mathbf{P(x) = (x + 3)^4}$

The degree is given as:

$\mathbf{n = 4}$

The zero is given as:

$\mathbf{x = -3}$

Add 3 to both sides

$\mathbf{x + 3= 0}$

From the question, we understand that the polynomial has a single zero.

So, the polynomial is:

$\mathbf{P(x) = (x + 3)^n}$

Substitute 4 for n

$\mathbf{P(x) = (x + 3)^4}$

Hence, the polynomial is $\mathbf{P(x) = (x + 3)^4}$

Read more about polynomials at:

brainly.com/question/11536910

3 0

2 years ago

Pls help asap, find the height of the cylinder and round to the nearest tenth

Elena L [17]

Answer:

h = 2.4

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

271.4 = pi ( 6)^2 *h

271.4 = 36* pi* h

Letting 3.14 = pi

271.4 = 113.04 h

Divide each side by 113.04

271.4 /113.04 = 113.04h/113.04

2.424805379 = h

Rounding to the nearest tenth

2.4 = h

OR if we use the pi button

271.4 = 36 * pi *h

Divide each side by 36 pi

271.4/36pi = h

h=2.3997

Rounding to the nearest tenth

h =2.4

3 0

2 years ago

What are the key aspects of the graph of f(x) = x2 – b2, where b is a real number?

netineya [11]

Given equation is $f\left(x\right)=x^2-b^2$ .

Now we need to find about what are the key aspects of the graph of $f\left(x\right)=x^2-b^2$ , where b is a real number.

We know that square of any number is always positive.

then $b^2$ must be a positive number.

So that means for any real number b, as the value of b increases then graph of f(x) shifts downward by $b^2$ units as compared to the graph of parent function $f\left(x\right)=x^2$