Factor to find the zeros of the function defined by the quadratic expression. −7x2 − 91x − 280

1 answer:

3 0

There are no zeroes for an expression, only for equations.
Assuming equation to be
<span>−7x^2 − 91x − 280=0
-7(x^2+13x+40)=0
-7(x+8)(x+5)=0
by the zero product properties,
x+8=0 => x=-8
or
x+5=0 => x=-5</span>

You might be interested in

Henry divided his socks into five equal groups. Let s represent the total number of socks. Which expression and solution represe

garik1379 [7]

Answer:

option A is correct answer of this question

hope yr day will full of charm

4 0

2 years ago

Read 2 more answers

Given 4,7,10,13. Calculate the 20th term.

Pavlova-9 [17]

Answer:

Step-by-step explanation:

to calculate the 20th term you use the formula

Tn=a+(n-1)d where a stands for the first term,n the number of terms and d the common difference.in this case the first term is 4 the common difference is 3 cause they were adding 3 to go to the next term.. therefore the solution will be:

Tn=4+(20-1)3

=4+19×3

=4+57

=61

the 20th term is 61

I hope this helps

7 0

2 years ago

Suppose that a cyclist began a 374 mi ride across a state at the western edge of the state, at the same time that a car traveli

kherson [118]

This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph

4 0

3 years ago

(HELP ME I CANT) Find the length of sides of ∆OTP if O is the centre of the circle ,PT is the length of

Ostrovityanka [42]

Hey there mate :)

Please check the attached image for answer.