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masya89 [10]
3 years ago
12

How does a loud sound differ from a soft sound?

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
6 0
You can hear it better
Vladimir79 [104]3 years ago
4 0
Well one is louder and one is softer lol idk how to answer this question
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Solve 4√2 + 5√4 and explain if the answer is rational or irrational
USPshnik [31]

Answer: Not Rational

Step-by-step explanation: because a rational number is a fraction, integer or a repeating decimal

5 0
3 years ago
Write an equation in slope-intercept form for this line.
iVinArrow [24]

Answer: y = 5/2x + 6

Step-by-step explanation:

y - y₁ = m(x - x₁)

y - (-9) = 5/2(x- (-6))

y + 9 = 5/2(x+ 6)

y +9 = 5/2x + 15

y = 5/2x + 15 - 9

y = 5/2x +6

6 0
3 years ago
My parents recently moved to the Poconos, they got 30 or more inches of
jekas [21]

Answer:

25ft

Step-by-step explanation:

2hr=10ft

5hr=25ft

5-2=3 so you have to find what they did for the 3 hours which is another 2 plus half so 25ft.

7 0
3 years ago
A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes
Elena L [17]

Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

Alternative hypothesis:p < 0.38  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

3 0
3 years ago
MERRY CHRISTMAS!!! pls help me with this and you will get the Christmas present you wanted!!plus brainlist lol
scoundrel [369]

Answer:

0.2

<em>Hope this helps!</em>

<em />

<em>xoxo,</em>

<em />

<em>cafeology</em>

7 0
3 years ago
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