Answer:
The answer is AAS.
Step-by-step explanation:
Since you have 2 angles that are the same and 1 side which are the same or congruent.
A = E
and C=C they are vertical angles so they are the same
And the AB and ED side are also same.
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
(predicted value - exact value)/exact value * 100
(31 - 34)/34 * 100 = 8.8%
A) Scale of map is 1: 30,000
This is assuming that it meant 1 centimetre = 30,000 metres, for it gives no other information.
Multiply 1 with 30,000: 30,000 x `1 = 30,000
30,000 metres is your answer.
B) Scale is 1 inch: 6 miles. You are given 2.5 inches.
Remember that 1 inch = 6 miles.
Multiply 2.5 to both sides: (2.5) * 1 inch = (2.5) * 6 miles
2.5 inch = 2.5 * 6 miles
2.5 inch = 15 miles
15 miles is your answer.
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