Answer:
Step-by-step explanation:
Let the solution to
2x^2 + x -1 =0
x^2+ (1/2)x -(1/2)
are a and b
Hence a + b = -(1/2) ( minus the coefficient of x )
ab = -1/2 (the constant)
A. We want to have an equation where the roots are a +5 and b+5.
Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.
The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.
So the equation is
x^2-(19/2)x + 22 =0
2x^2-19x + 44 =0
B. We want the roots to be 3a and 3b.
Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and
(3a)(3b) = 9(ab) =9(-1/2)=-9/2.
So the equation is
x^2 +(3/2) x -9/2 = 0
2x^2 + 3x -9 =0.
Step-by-step explanation:
x+y=5
3x-2y+5=0
3x-2y= -5
x+y=5...... equation 1
3x-2y= -5....... equation 2
there fore make x the subject of the formula in equation 1
x=5-y.. equation 3
substitute equation three in equation 2
3(5-y)-2y=-5
15y-3y-2y=-5
10y=-5
divide both sides by 10
y=-5/10
y=-½
substitute y into equation 1
x+(-½)=5
x=5+½
x=5½
x=5½,y= -½
Answer:
Step-by-step explanation:
Chords having equal measures are equidistant from the center of the circle.
Since, VW = XY
Therefore, ZP = ZR = 15 units
A perpendicular line drawn from the center of a circle to the chord is the bisector of the chord.
VR = WR = 20 units
By applying Pythagoras theorem in ΔZRV,
ZV² = ZR² + VR²
ZV² = (15)² + (20)²
ZV = √(225 + 400)
ZV = √625
ZV = 25 units
Therefore, measure of radius ZV = 25 units.
VW = XY [Given]
Therefore, XY = 2(20)
= 40 units
Answer: the answer is a hard doosie
Step-by-step explanation:
Answer:
52.5 adult tickets
52 rounded
Step-by-step explanation:
