The answer for your question question is 3+ 16/3 i
2 or a few months. This should be the answer
Given the list of numbers, 3, 2, 6, 3, 9, 5, 12, 7, if the pattern continues, what is the sum of the ninth and tenth numbers?
LekaFEV [45]
Answer:
Step-by-step explanation:
Every other one beginning with the first 3 adds 3 to the preceding number that has an odd position.
So the odd positions go up 3 6 9 12
And the next odd position is 15 which is the nineth term.
It's hard to tell what the even ones are doing. It could be anything just about. I'm guessing its a 9. So the tenth term is 9.
The sum of 9 and 15 = 24
If someone gives you a more consistent answer, take it.
Answer:
X ~ N(27, 4) ;
xbar ~ N(27, 0.1026) ;
0.5 ;
0.5
Step-by-step explanation:
Probability distribution of X : N(μ, σ²)
μ = 27 ; σ = 2
X ~ N(μ, σ²) = X ~ N(27, 2²) ;X ~ N(27, 4)
Distribution is approximately normal ; μ = xbar ; xbar = 27
(Standard Error)² = (σ/√n)²= (2/√39)² = 0.1026
xbar ~ N(μ, σ²) = xbar ~ N(27, 2²) ; xbar ~ N(27, 0.1026)
Probability that a randomly selected individual found a job in less than 27 weeks :
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ
Z = (27 - 27) / 2 = 0/2
Z = 0
P(Z < 0) = 0.5
D.) n = 36
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ/√n
Z = (27 - 27) / (2/√36) = 0/0.33333
Z = 0
P(Z < 0) = 0.5
3( -4 ) = y - 5
-12 = y - 5
y = -7
