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katrin [286]
3 years ago
5

2 1/2= to another mixed number

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0
I’m confused also but yes could be 2 2/4 but could also be 1 2/1
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Please help!!!!!!!!!!!
irina [24]

Step-by-step explanation:

<h3>y = 9 and x = 16 <u> </u><u> </u><u>Ans</u><u>.</u><u> </u></h3>

Hope it can help u :)

3 0
3 years ago
Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems
Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for (x_{1},y_{1})  and (x_{2},y_{2})

Use the distance formula to find the length =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length =\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\

length = \sqrt{80}

length = 8.94

Use the distance formula to find the width =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width =\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\

width =\sqrt{(-10 )^{2} + (11 )^{2}}\\

width =\sqrt{100 + 121}\\

width = \sqrt{221}

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0
3 years ago
What is a area of a figure with 9.9 3.3 5.4
Helga [31]
9*9=81
3*3=9
5*4=20
20+9=29
29+81=110 final answer
3 0
3 years ago
Find the inverse please and thank you
Amanda [17]

The inverse f^{-1}(x) is such that

f\left(f^{-1}(x)\right) = x

We have

f\left(f^{-1}(x)\right) = -9\sqrt{f^{-1}(x) - 8} + 5 = x

Solve for the inverse.

-9\sqrt{f^{-1}(x)-8} + 5 = x \\\\ -9\sqrt{f^{-1}(x)-8} = x-5 \\\\ \sqrt{f^{-1}(x)-8} = -\dfrac{x-5}9 \\\\ \left(\sqrt{f^{-1}(x)-8}\right)^2 = \left(-\dfrac{x-5}9\right)^2 \\\\ f^{-1}(x) - 8 = \dfrac{(x-5)^2}{81} \\\\ \boxed{f^{-1}(x) = 8 + \dfrac{(x-5)^2}{81}}

5 0
2 years ago
Point m is between point x and y and xm=my t
Elenna [48]
XY is a line. If M is the middle of that line, then XM will be the same length as MY.<span>
</span>
4 0
3 years ago
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