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Leviafan [203]
3 years ago
10

150 between_and_ Guess check

Mathematics
1 answer:
MAXImum [283]3 years ago
5 0
150 is between 149 and 151
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PLEASE HELP! I WILL MARK YOU AS BRAINLIEST!
velikii [3]

Answer:

10 cm²

Step-by-step explanation:

The area of a square = s², where s is the measure of the side

To calculate the side use Pythagoras' identity

Consider the lower side with right triangle legs 3 and 1, then

side² = 3² + 1² = 9 + 1 = 10 ( take the square root of both sides )

side = \sqrt{10}, thus

area = (\sqrt{10} )² = 10 cm²

7 0
3 years ago
Read 2 more answers
Translate 5 times the sum of 7 and n
11111nata11111 [884]

Answer:

5( 7+n)

Step-by-step explanation:

First find the sum

(7+n)

Then multiply by 5

5( 7+n)

4 0
3 years ago
Read 2 more answers
Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr
NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:  

  • \sqrt{(8-x)}^2=8-x

Distance between point (x,0) and Springfield(0,7) is:

\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}

Distance between point (x,0) and Shelvyfield(0,-7) is:

\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}

Therefore the Length of the Cable L(x)

  • L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}

To find the critical point, we set the derivative of L(x)=0

L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}

\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993

Since L^{''}(x)  is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0
3 years ago
A store has 25% off sale on coats. With this discount the price of one coat is $34.50
lakkis [162]
43.125
34.50 \times .25 = 8.625 = 43.125
5 0
4 years ago
Read 2 more answers
1.6×(3+2)÷10
shusha [124]
1. 6×(3+2)÷10 = 3

Work:
3+2 = 5
6 × 5 = 30
30 ÷ 10 = 3

2. 12-(3×3)+11 = 14

Work:
3 × 3 = 9
12 - 9 = 3
3 + 11 = 14

3. (10×0.4) + (10×0.8) = 12

Work:
10 × .4 = 4
10 × .8 = 8
8 + 4 = 12

4.(8 ÷ 4)×(4-2) = 4

Work:
8 ÷ 4 = 2
4 - 2 = 2
2 × 2 = 4

5.8.5-10÷2 = 3.5

Work:
10 ÷ 2 = 5
8.5 - 5 = 3.5

6.18-(8÷2)+25 = 39

Work:
8 ÷ 2 = 4
18 - 4 = 14
14 + 25 = 39
6 0
3 years ago
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