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3 years ago

The value of 7mn to the 2power, for m = 3 and n = -2

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

You mean (7mn)^2, if so...

(7*3*-2)^2

-42^2=1764

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In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

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3 years ago

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What is the rule in the input/output table? A) add 4 B) subtract 4 C) divide by 2 D) multiply by 2 | inputs | 4 6 and 8 | output

MissTica

The rule in the input/out is D multiply by 2

4 0

3 years ago

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5u + 14 > 64 Can someone tell me what U is?

ale4655 [162]

5u > 64 - 14
5u > 50
u > 10

7 0

3 years ago

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Plz help me well mark brainliest if correct!!...

valina [46]

Answer:

You should stick with option D

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3 years ago

An arc with length 5 pi over 4 inches is formed by a 15 degree central angle what is the radius of the circle

Natalka [10]

Answer:

Radius of the circle is 15 inches.

Step-by-step explanation:

Relation between length of arc, radius and the angle subtended by the arc on center is:

$\theta = \dfrac{l}{r} ..... (1)$

where $\theta$ is the central angle in radians subtended by arc

$l$ is the length of arc

$r$ is the radius of arc

We are Given the following details:

$l = \dfrac{5\pi}{4}\ inch$

$\theta = 15^\circ$

We know that $\pi \ radians = 180 ^\circ$

Converting $\theta$ to radians:

$\theta =\dfrac{\pi}{180} \times 15$ radians

Putting the values of $\theta$ and $l$ to find the value of $r$

$\dfrac{\pi}{180} \times 15 = \dfrac{5\pi}{4r}\\\Rightarrow r = \dfrac{45}{3} \\\Rightarrow r = 15 \ inches$

Hence, Radius of the circle is 15 inches.

6 0

3 years ago