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2 years ago

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De lenguaje común a algebraico:La altura (h) de un triángulo equilátero es igual a la raíz de la diferencia

1 answer:

Elis [28]2 years ago

8 0

La respuesta es 6.92 en su expresión más pequeña porque dice la altura de un triángulo equilátero es igual solo sacas las fórmula de la altura de un triángulo que es a^2=c^2+B^2 osea haci que sustituye con valores h^2= 8^2-4^2=h^2 8x8=64 4x4=16 64-16= √48 = 6.92

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Will mark BRAINLIST Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral

kolbaska11 [484]

Answer:

11.3 units

Step-by-step explanation:

Let's find the length of one of the boxes.

$a^2+b^2=c^2\\1^2+1^2=c^2\\1+1=c^2\\2 = c^2\\\\\sqrt{2} = c\\ c = 1.414...$

Let's simplify c down to 1.41.

Now, there are 8 of these little boxes for the perimeter, let's multiply.

$1.41\cdot8=11.28$

That can be simplified to the nearest tenth - 11.3

Hope this helped!

8 0

3 years ago

Which of the following dose NOT have any rectangular faces? A. Pentagonal prism B. Hexagonal pirámide C. Rectangular prisa D. Sq

Artemon [7]

Dear Sweet21574, the answer is D. Squre pyramid.

8 0

2 years ago

Which is a true statement? A. –3.62 < –3.5 B. 0.8 > 7.1 C. 6.25 < 6.2 D. –3.4 > –3.3

Troyanec [42]

A is correct :)

Hope this helps!

3 0

2 years ago

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

2 years ago

How do I do this step by step?<br><br> 3(y-2) +5y = y+22

tatiyna

Answer:

3(Y-2) +5Y =Y+22

3Y-6 +5Y=Y+22

3Y -6 +5Y-Y-22=0

3Y+5Y-Y-6-22=0

7Y-28=0

7Y=28

Y=28/7

Y=4

Step-by-step explanation:

7 0

2 years ago