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hjlf
4 years ago
10

Please help

Mathematics
2 answers:
vladimir1956 [14]4 years ago
8 0
It would be supplementary because the angles outside the triangle are connected though the line segment of the triangle.
Goshia [24]4 years ago
6 0
It forms Obtuse angle......
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According to a recent​ poll, 25​% of adults in a certain area have high levels of cholesterol. They report that such elevated le
Readme [11.4K]

Answer:

The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\for\ a \ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\where\ x=raw\ score,\mu=mean, \sigma=standard deviation

Given that n = 49, μ = 260 mg/dL, σ = 35 mg/dL

a) For x < 210:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{210-260}{35/\sqrt{49} } =-10

From the normal distribution table, P(x < 210) = P(z < -10) = 0.0001

b) For x > 205:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{205-260}{35/\sqrt{49} } =-11

For x < 215:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{215-260}{35/\sqrt{49} } =-9

P(205 < x < 215) = P(-11 < z < -9) = P(z < -9) - P(z < -11) = 0.0001 - 0.00001 = 0.00009

c) For x < 200:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{200-260}{35/\sqrt{49} } =-12

From the normal distribution table, P(x < 200) = P(z < -12) = 0.00001

d) For x > 222:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{222-260}{35/\sqrt{49} } =-7.6

From the normal distribution table, P(x > 200) = 1 - P(z < -12) = 1 - 0.0001 = 0.9999

7 0
3 years ago
In a test, +3 marks are given for every correct answer and -1 mark are given for every incorrect answer. Sona attempted all the
Marizza181 [45]


x = number of questions

3y = points for a correct answer
-1x or -x = points for an incorrect answer

Adding up the correct and incorrect points/answers gives us the final score. We can solve to see how many questions were incorrect. (We are told 10 were correct)

3y + (-1x) = 20
3(10) + (-1x) = 20
30 - x = 20
10 = x
x = 10

So she got 10 correct and 10 incorrect, and there were 20 questions in all.

3 0
3 years ago
Identify The domain of the rational function, g(x)= 1/x+3
8_murik_8 [283]

Answer:

The domain is (-∞ , -3) ∪ (-3, ∞) ⇒ D

Step-by-step explanation:

<em>The domain of the rational fraction is t</em><em>he values of x which make the fraction defined</em><em>. That means </em><em>the domain does not contain the values of x which make the denominator equal to 0</em><em>.</em>

∵ g(x) = \frac{1}{x+3}

∴ The denominator = x + 3

→ Equate the denominator by 0

∵ x + 3 = 0

→ Subtract 3 from both sides

∴ x + 3 - 3 = 0 - 3

∴ x = -3

→ That means the domain can not have -3 because it makes the denominator

   equal to 0

∴ The domain is all values of real numbers except x = -3

∴ The domain = {x : x ∈ R, x ≠ -3}

∴ The domain = (-∞ , -3) ∪ (-3, ∞)

4 0
3 years ago
What is the value of c in this linear system? <br> A) 1<br> B) -3<br> C) -1<br> D) 2
Alika [10]

9514 1404 393

Answer:

   B)  -3

Step-by-step explanation:

There are methods for finding only c. Cramer's rule is one of them. It involves finding two determinants and taking their ratio. Here, we choose a more <em>ad hoc</em> approach. It appears that the value of b can be found by combining the last two equations.

  (1/2)(2a +4b -2c) -(a -3b -c) = (1/2)(12) -(-4)

  5b = 10

  b = 2

Now, we can substitute this value into the first two equations. This gives ...

  5a +c = -8

  a - c = 2

Subtracting 5 times the second from the first gives ...

  (5a +c) -5(a -c) = (-8) -5(2)

  6c = -18 . . . . simplify

  c = -3 . . . . . . divide by 6

The value of c is -3.

4 0
3 years ago
An engineer is designing a runway for an airport. Several planes will use the runway and the engineer must design it so that it
swat32

Answer:

d=117.33 m

Step-by-step explanation:

Initial velocity of planes, u = 0 (because they are at rest)

Acceleration, a = 3.3 m/s²

Final take off speed, v = 88 m/s

We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}

Putting all the values, we get :

d=\dfrac{88^2-0^2}{2\times 33}\\\\d=117.34\ m

Hence, the minimum allowed length for the runway is 117.33 m.

3 0
3 years ago
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