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4 years ago

Please help

2 answers:

vladimir1956 [14]4 years ago

8 0

It would be supplementary because the angles outside the triangle are connected though the line segment of the triangle.

Goshia [24]4 years ago

6 0

It forms Obtuse angle......

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According to a recent poll, 25% of adults in a certain area have high levels of cholesterol. They report that such elevated le

Readme [11.4K]

Answer:

The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\for\ a \ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\where\ x=raw\ score,\mu=mean, \sigma=standard deviation$

Given that n = 49, μ = 260 mg/dL, σ = 35 mg/dL

a) For x < 210:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{210-260}{35/\sqrt{49} } =-10$

From the normal distribution table, P(x < 210) = P(z < -10) = 0.0001

b) For x > 205:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{205-260}{35/\sqrt{49} } =-11$

For x < 215:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{215-260}{35/\sqrt{49} } =-9$

P(205 < x < 215) = P(-11 < z < -9) = P(z < -9) - P(z < -11) = 0.0001 - 0.00001 = 0.00009

c) For x < 200:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{200-260}{35/\sqrt{49} } =-12$

From the normal distribution table, P(x < 200) = P(z < -12) = 0.00001

d) For x > 222:

$z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{222-260}{35/\sqrt{49} } =-7.6$

From the normal distribution table, P(x > 200) = 1 - P(z < -12) = 1 - 0.0001 = 0.9999

7 0

3 years ago

In a test, +3 marks are given for every correct answer and -1 mark are given for every incorrect answer. Sona attempted all the

Marizza181 [45]

x = number of questions

3y = points for a correct answer
-1x or -x = points for an incorrect answer

Adding up the correct and incorrect points/answers gives us the final score. We can solve to see how many questions were incorrect. (We are told 10 were correct)

3y + (-1x) = 20
3(10) + (-1x) = 20
30 - x = 20
10 = x
x = 10

So she got 10 correct and 10 incorrect, and there were 20 questions in all.

3 0

3 years ago

Identify The domain of the rational function, g(x)= 1/x+3

8_murik_8 [283]

Answer:

The domain is (-∞ , -3) ∪ (-3, ∞) ⇒ D

Step-by-step explanation:

The domain of the rational fraction is the values of x which make the fraction defined. That means the domain does not contain the values of x which make the denominator equal to 0.

∵ g(x) = $\frac{1}{x+3}$

∴ The denominator = x + 3

→ Equate the denominator by 0

∵ x + 3 = 0

→ Subtract 3 from both sides

∴ x + 3 - 3 = 0 - 3

∴ x = -3

→ That means the domain can not have -3 because it makes the denominator

equal to 0

∴ The domain is all values of real numbers except x = -3

∴ The domain = {x : x ∈ R, x ≠ -3}

∴ The domain = (-∞ , -3) ∪ (-3, ∞)

4 0

3 years ago

What is the value of c in this linear system? A) 1 B) -3 C) -1 D) 2

Alika [10]

9514 1404 393

Answer:

B) -3

Step-by-step explanation:

There are methods for finding only c. Cramer's rule is one of them. It involves finding two determinants and taking their ratio. Here, we choose a more ad hoc approach. It appears that the value of b can be found by combining the last two equations.

(1/2)(2a +4b -2c) -(a -3b -c) = (1/2)(12) -(-4)

5b = 10

b = 2

Now, we can substitute this value into the first two equations. This gives ...

5a +c = -8

a - c = 2

Subtracting 5 times the second from the first gives ...

(5a +c) -5(a -c) = (-8) -5(2)

6c = -18 . . . . simplify

c = -3 . . . . . . divide by 6

The value of c is -3.

4 0

3 years ago

An engineer is designing a runway for an airport. Several planes will use the runway and the engineer must design it so that it

swat32

Answer:

d=117.33 m

Step-by-step explanation:

Initial velocity of planes, u = 0 (because they are at rest)

Acceleration, a = 3.3 m/s²

Final take off speed, v = 88 m/s

We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}$

Putting all the values, we get :

$d=\dfrac{88^2-0^2}{2\times 33}\\\\d=117.34\ m$

Hence, the minimum allowed length for the runway is 117.33 m.

3 0

3 years ago