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shepuryov [24]
3 years ago
5

What is the answer for 4y^2=81

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer:

y = ± 4.5.

Step-by-step explanation:

Given : 4y²=81

To find : Solve for y

Solution : We have given that

4y²=81

On dividing by 4 both sides

y²= \frac{81}{4}

y²= 20.25

On taking square root both sides

y = \sqrt{20.25}

y = ± 4.5

Therefore, y = ± 4.5.

Elena L [17]3 years ago
3 0
<span><u><em>Answer:</em></u>
either y = 4.5
or y = -4.5

<u><em>Explanation:</em></u>
To get the solution, we will need to isolate the y on one side of the equation.
<u>This can be done as follows:</u>
4y</span>²<span> = 81

</span>\frac{4y^2}{4} =  \frac{81}{4}
<span>
y</span>²<span> = 20.25

y = +/- </span>√(20.25)<span>
either y = +</span>√<span>(20.25) = 4.5
or y = -</span>√<span>(20.25) = -4.5

Since there are no restrictions on the value of y, therefore, both answers would be accepted

Hope this helps :)</span>
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All the students in a school were weighed. Their average weight was 30.8 kilograms, and their total weight was 16,293.2 kilogram
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Answer: 529 students

Step-by-step explanation:

To solve this, we will be using the formula for finding averages:

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Plugging in the values that are given in the problem, you get:

> 16,293.2 ÷ x = 30.8

Where x is equal to the total sum of students. From here, it's a simple equation to isolate x, and find out what numerical value x is equal to. In case you are unsure how to do this, I've created a clear step by step process for how to do this (NOTE: The slash represents division, while the asterisk represents multiplication.):

> 16,293.2 / x = 30.8

> (16,293.2 / x) * x = (30.8) * x

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7 0
2 years ago
The value of a stock drops 4 points each day for five straight days. What is the net change in the value of the stock? Write you
Fantom [35]

Answer:

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Step-by-step explanation:

The value of a stock drops 4 points each day for five straight days

Lets assume initial value of stock to be $ y

Now lets reduce this value by 4 for 5 straight days

Day                                new stock value in $         daily change as an Integer

Day 1                                   y-4                                  (y-4)-y= y-4-y = -4

Day 2                                 (y-4)-4 = y-8                  (y-8)-(y-4) =y-8-y+4= -4

Day 3                                  (y-8)-4 = y-12               (y-12)-(y-8)= y-12-y+8 = -4

Day 4                                  (y-12)-4 = y-16              (y-16)-(y-12)=y-16-y+12=-4

Day 5                                   (y-16)-4 = y-20           (y-20)-(y-16)=y-20-y+16=-4

The final value of stock in day 5 will be $ y-20

The net change is the difference in value of stock at day 1 and day 5

Day 1 = $ y

Day 5 = $ y-20

Net change= $(y-20)-$y

=y-20-y = -20

=20

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