A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
The answer is C. loss section
Answer:
Rotate 90 degrees clockwise around the origin and then translate down. Reflect across the x-axis and then reflect across the y-axis.
Step-by-step explanation:
Reflection across the y-axis. 90o counter clockwise rotation. 2. Multiple-choice. 1 minute. Q. Identify the transformation from ABC to A'B'C'. Draw the final image created by reflecting triangle RST in the x-axis and then rotating the image 90° counterclockwise about the origin. BER goo Clockwise 90c ...C-level G2-1 Reflections and Rotations ... X-axis. 00. G2-2 Rotations. 4. Rotate the figure 90° clockwise around the origin. ... Rotation 90° counter.
Answer:
<em>Type 7.5 in the box!</em>
Step-by-step explanation:
Consider the trapezoid formula ( ( base 1 + base 2 ) / 2 ) * height;
<em>Area = 7.5 square units</em>
