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inessss [21]
4 years ago
7

Solve abc given that C=32 b=8 a=3

Mathematics
1 answer:
aev [14]4 years ago
7 0
The answer to (a)(b)(c) is 2,656
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Please help, Math test question !
Naily [24]

Answer:

Mat has 6 cookies. He divides them among his 8 friends. How many cookies does each person get?

Step-by-step explanation:

You divide 6 by 8..?

6 0
3 years ago
-11.2+4(2.1+q) = -0.8<br>solve and can you explain how to solve? I am confused 
Gekata [30.6K]
Given
-11.2+4(2.1+q) = -0.8

Take -11.2 to the right hand side of the equation (sign will change when we move it to the other side)
∴ 4(2.1+q) = -0.8 + 11.2

Simply both sides
∴ 4*2.1 + 4*q = 11.2-0.8
∴ 8.4 + 4q = 10.4

Take 8.4 to the right hand side
∴ 4q = 10.4 - 8.4
∴ 4q = 2
∴ q = 2/4
∴ q = 1/2 = 0.5
6 0
4 years ago
Read 2 more answers
choose the answer based on the most efficient method. if the first step in the equation " -9 + x = 5x - 7" is subtract x, what s
Lady bird [3.3K]

Answer:

add 7 to both sides

Step-by-step explanation:

This is so because we are trying to solve the equation by seperating the variables from the real numbers. So as they remove all variables from the left side of the equation, we should remove any remaining numbers that are on the right side of the equation.

Hope this helps!

6 0
3 years ago
Which of the following functions has a range of all real numbers?
serious [3.7K]
Only the function in C has the range of all real numbers.
Later on, when you will be familiar with more type of functions you will know that when x is on the power range is usually only positive values or negative values if only not shifted, even if shifted it will only add to its range this numbers by which unit it was shifted.
B is shifted parabola. It has the range of  {y| -3≤∞}
6 0
3 years ago
A study was conducted to determine whether there were significant differences between medical students admitted through special
Mekhanik [1.2K]

Answer:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

Step-by-step explanation:

Let X the random variable of interest "number of  students graduated", on this case we now that:  

X \sim Binom(n=10, p=0.913)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

3 0
4 years ago
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