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Masja [62]
3 years ago
12

What multiple of 10 can be used to remove the decimals and fractions in this equation?

Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Sorry, this was the answer to the wrong question, I'm very sorry for the inconvenience.

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U can do any problem
IrinaVladis [17]

Answer:

For question 14

The answer is x= 52%

Step-by-step explanation:

5 0
2 years ago
SOMEONE HELP ME PLS<br><br> Solve for x.
faltersainse [42]

Answer:

X equals 6°.

Step-by-step explanation:

There is a geometry rule that states the outer angle of a triangle's interior angle is equivalent to the sum of the remaining two interior angles of the triangle. Following this rule, you can get that (6x + 8) + (5x + 8) = 82° ⇒ 11x + 16 = 82° ⇒ 11x = 66° ⇒ x = 6°.

6 0
3 years ago
Find the sum.<br> negative 4 plus 16
lorasvet [3.4K]

Answer:

postive 12

Step-by-step explanation:

16-4=12


6 0
3 years ago
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Harriet has 3/4 tank of gas left in her car. if she needs 1/4 tank to go to her friends house and another 1/4 tank to get back h
KATRIN_1 [288]
Yes she does have enough. Here is why: If you add 1/4 and 1/4, you get 2/8 which is also 1/2. 3/4 is bigger than one half. If you subtract 1/2 from 3/4, you get 1/4. So she would have 1/4 left. Absolutely enough to get to her friends house and back. :)
3 0
3 years ago
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A semi-circular garden has an area of 18pie m2 what is the perimeter of the garden
nataly862011 [7]

Answer:

6\pi

Step-by-step explanation:

We know that the area of a circle is equal to \pir^{2}.

A semi-circle is a half-circle, meaning that it will have half of the area of a full circle.

Therefore, a semi-circle's area is equivalent to \frac{\pi r^{2} }{2}.

Set this equation equal to 18\pi.

Solve for r.

We then find that r = 6.

Now, we need to find the circumference. We know that the equation for the circumference of a circle is 2\pir. Since we only need the perimeter of half of a circle, our circumference equation will equal \pir.

Plug 6 in for r.

The perimeter of the garden is equal to 6\pi.

7 0
2 years ago
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