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Tema [17]
3 years ago
14

Can someone help with this algebra problem please 100% correct only

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0
You have to write an equation that can help you solve the problem like x + 4 = 26 then solve for x.
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In the diagram, m∠3 = 120° and m∠12 = 80°. Which angle measures are correct? Check all that apply.
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200•druggy KJV yodels malani real Jamal um r Iquitos is this week for you to join us and I wanna know we’re gonna I gotta remember way to
7 0
4 years ago
3(2x-7=5-(1-x) pls help me
vekshin1

Answer:

 3 • (2x - 7) -  (x + 4)  = 0

then do 3.1     Pull out like factors :

  5x - 25  =   5 • (x - 5)

 5 • (x - 5)  = 0

4.2      Solve  :    x-5 = 0

Add  5  to both sides of the equation :

                     x = 5

Step-by-step explanation:

7 0
3 years ago
ANSWER ASAP PLEASE & SHOW UR WORK!!!
Lina20 [59]

Answer:

x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}

Step-by-step explanation:

<u>Biquadratic Equations</u>

Solve:

x^4 + 3x^2 - 18 = 0

The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.

Solving such equations requires to express the equation as a second-degree equation with x^2 as the variable.

Rewriting the equation:

(x^2)^2 + 3(x^2) - 18 = 0

The quadratic equation can be factored as:

(x^2+6)(x^2-3)=0

It leads to two equations:

x^2+6=0

x^2-3=0

The first equation has imaginary roots. Solving for x:

x^2=-6

x=\pm\sqrt{-6}

x_1=\mathbf{i}\sqrt{6}

x_2=-\mathbf{i}\sqrt{6}

Where

\mathbf{i}=\sqrt{-1}

The second equation has two real roots:

x^2-3=0

x^2=3

x=\pm\sqrt{3}

x_3=\sqrt{3}

x_4=-\sqrt{3}

The roots are:

\mathbf{x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}}

3 0
3 years ago
I NEED ANSWER ASAP!!! PLEASE HELP!!! A shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angl
krek1111 [17]
The horizontal component of the velocity of the shot is 35 cos 40 ft/sec which is constant
Therefore:-
Velocity = distance / time
35 cos 40  = 40 / t

t = = 40 / 35cos40  =  1.49 seconds to nearest hundredth

4 0
3 years ago
Central and Inscribed Angles Worksheet<br><br>PLEASE SOLVE ALL THE QUESTIONS!!!​
Andru [333]

This question have no solution. Sorry!

7 0
4 years ago
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