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4 years ago

I need help on this question plz

Mathematics

2 answers:

Mekhanik [1.2K]4 years ago

7 0

A reflection would keep the object the same size but move it to a different Quadrant.

A translation would also keep the object the same size, just move it to a new location.

A rotation would keep the object the same size, but change the oriatation of the shape.

A dilation would change the size of the original shape to either a smaller or larger size.

The above image is a dilation.

Crazy boy [7]4 years ago

6 0

the answer is dilation

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Olin [163]

Answer:

Step-by-step explanation:

definitely b because 6 percent of 2000 is 120 and 120 x 2 is 240 so add that to the 2000 and theres your answer

7 0

3 years ago

Read 2 more answers

20 POINTS Which of the following tables does NOT represent a function?

pashok25 [27]

Answer:

Step-by-step explanation:

In a function, one x-value must have just one y-value assigned to it. So in short, C is the only table that does not represent a function because it has two values of Y (-3, and -1) for one value of x (1).

7 0

2 years ago

Drag numbers to write an equation for the line in slope-intercept form. Numbers may be used once, more than once, or not at all.

Volgvan

Answer:

Slope: -4

Y-intercept: 5

Step-by-step explanation:

The slope goes down 4 and over one which means that the slope is -4.

When X is 0, Y is 5

Good Luck!!

5 0

3 years ago

asappp please someone help i’ll give brainliest. i’m trying to find x, and by what form like ASA, etc

Alex777 [14]

Answer:

x = 40.375

Step-by-step explanation:

∠A≅∠E, ∠B≅∠F and ∠C is common and congruent to itself, therefore

ΔABC ~ ΔEFC by AA similarity

Ratio of corresponding sides is same. Get the equation below and solve for x:

EC/AC = CF/CB
x/17 = (16+22)/16
x/17 = 38/16
x/17 = 19/8
x = 17*19/8
x = 40.375

3 0

3 years ago

Select the exclusion that fits best with this problem.

nalin [4]

Answer:

$\frac{1}{2y-2y^2}, y\neq 1$

Step-by-step explanation:

observe by factorization and cancelation

$\frac{y^2+y+1}{-2y(y^3-1)}=\frac{y^2+y+1}{-2y(y-1)(y^2+y+1)}\\=\frac{1}{-2y(y-1)}\\=\frac{1}{2y-y^2}$

7 0

3 years ago