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SOVA2 [1]
3 years ago
15

ABC Bookstore sells new books according to the demand function P = -Q + 25, where P is the price and Q is the quantity. If the b

ookstore charges $18 for a new book, how many new books can the store expect to sell?
Mathematics
2 answers:
Ghella [55]3 years ago
4 0
P = -Q + 2518 = -Q + 2518-25 = -Q-7 = -Q-7/-1 = -Q/-1Q = 7
Therefore, the store can expect to sell 7 new books if they will charge $18 for the new books. 
vekshin13 years ago
3 0

Answer:

P = -Q + 2518 = -Q + 2518-25 = -Q-7 = -Q-7/-1 = -Q/-1Q = 7

Therefore, the store can expect to sell 7 new books if they will charge $18 for the new books.



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Brainliest and 30 points please help
kolbaska11 [484]

Answer:

22. Perimeter = 52 units

     Area = 160 Square Units

23. Notation form :  2 \times 10^{5}

     Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

  = 2 ( 2x+3x+1)

  =  2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= 2x \times (3x+1)

A=6x^2+2x

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}

\frac{2.8}{1.4} \times 10^{9-4}

2 \times 10^5

Priya's calculation

\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}

\frac{2.8}{1.4} \times 10^{2-(-3)}

2 \times 10^5

Standard notation

2 \times 10^5 = 200000

4 0
3 years ago
Please help! Will mark brainless​
KengaRu [80]
Here’s what you can do to make this very simple. Consider that the “missing” space between the rectangles isn’t there. Then, find the area:

10 x 9 = 90 mm

Now, find the area of the “missing” part.

5 x 2 = 10 mm

Finally, you deduct the missing part from the complete rectangle!

90 - 10 = 80 mm

The area of this whole thing is 80 mm!

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The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


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