Which of the following is the number of sides for a regular polygon that will

I EILL MAKE BRAINLEST NEED HELP ASAP MT TEACHER IS ABOUT TO YELL WT ME PLEASE PLEASE PLEASE PLEASE PLEASE

Korvikt [17]

Ok, what class is this

8 0

2 years ago

Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45

VMariaS [17]

Based on the information given, the computation shows that the distance between them is 2.47 miles.

<h3>Solving the distance.</h3>

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

Learn more about distance on:

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8 0

1 year ago

Part A- Create a fourth degree polynomial in standard form. How do you know it is in standard form?

Alexeev081 [22]

Answer:

(a) $2x^4-9x^3+x^2+x-5$

Step-by-step explanation:

(a)The degree of a polynomial is the highest power of the unknown variable in the polynomial.

A polynomial is said to be in standard form when it is arranged in descending order/powers of x.

An example of a fourth degree polynomial is: $2x^4-9x^3+x^2+x-5$

We know the polynomial above is in standard form because it is arranged in such a way that the powers of x keeps decreasing.

(b)Polynomials are closed with respect to addition and subtraction. This is as a result of the fact that the powers do not change. Only the coefficients

change. This is illustrated by the two examples below:

$(2x^5-3x^2+x)+(3x^5-5x^2)\\=2x^5-3x^2+x+3x^5-5x^2\\=5x^5-8x^2+x\\$Similarly\\(2x^5-3x^2+x)-(3x^5-5x^2)\\=2x^5-3x^2+x-3x^5+5x^2\\=-x^5+2x^2+x$

The degrees do not change in the above operations. Only the number beside each variable changes. Therefore, the addition and subtraction of polynomials is closed.

7 0

2 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

There are 35 birds in a tree. Then 17 flew away. How many birds are tin the tree now. Regroup a ten.

alexira [117]

18 birds are left then regroup a ten 28 I hope it’ helps

4 0

2 years ago

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