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Sloan [31]
3 years ago
5

Simplify sin(180-theater).cos(90°-theater)-1/cos(-theater)

Mathematics
1 answer:
Harman [31]3 years ago
3 0
[sin(180-a) x cos(90-a) - 1]/cos(-a)
= [sin(a) x sin(a) - 1]/(-cos(a))
= [sin^2(a) -1]/(-cos(a))
= [-cos^2(a)]/(-cos(a))
= cos(a)

formula used
sin(180-a) = sin(a)
cos(90-a) = sin(a)
cos(-a) = -cos(a)
sin^2(a) + cos^2(a) = 1
all of these are easily proved by the unit circle. you might find someone to explain this. it will be very handy.
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Given f(x)=3x^2+5 and g(x)=x−2 . What is (fg)(x) ? 3x^2−x+7 3x^3−6x2+5x−10 −3x^2+x−7 3x^3−10
wolverine [178]

For this case we have that by definition:

(fg) (x) = f (x) * g (x)

So:

(fg) (x) = (3x ^ 2 + 5) (x-2)

We apply distributive property that states that:

(a + b) (c + d) = ac + ad + bc + bd

In addition, we take into account that:

+ * - = -

(fg) (x) = 3x ^ 3-6x ^ 2 + 5x-10

Answer:

3x ^ 3-6x ^ 2 + 5x-10

Option B

6 0
2 years ago
Read 2 more answers
Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
alekssr [168]

Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

                       = mod (25-75+0-75) ÷ 2

                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

4 0
2 years ago
X* square root of 3 =34
disa [49]

Answer:

17.49286

Step-by-step explanation:

Photomath :)

4 0
2 years ago
Read 2 more answers
Evaluate a(4b + c2) if a = 2, b = 5, and c = 1.
Maksim231197 [3]

Answer:

42

Step-by-step explanation:

a = 2, b = 5, and c = 1

  • a*(4b + c²) =               ⇒ plug in values
  • 2*(4*5 + 1²) =              ⇒ solving exponents
  • 2*(20 + 1) =                 ⇒ parenthesis
  • 2*21 =                         ⇒ multiplication
  • 42                               ⇒ answer
3 0
3 years ago
Read 2 more answers
4. k/6 = 8/16 5. 5.4/7 = 27/h 6. 8/11 = 4/y+2
kupik [55]

Answer:

4. k=3\\

5. h=35

6. \frac{7}{2} or 3.5

Step-by-step explanation:

\frac{k}{6}=\frac{8}{16}

Multiply those 2 values whose diagonal has both terms and divide by the term whose diagonal has the variable.

k=\frac{8*6}{16}\\ k=\frac{48}{16}\\ k=3

-----------------------------------------------------------------------

\frac{5.4}{7}=\frac{27}{h}

h=\frac{7*27}{5.4} \\h=\frac{189}{5.4}\\ h=35

-------------------------------------------------------------------------

\frac{8}{11}=\frac{4}{y+2}

y+2=\frac{11*4}{8}\\ y=\frac{11*4}{8}-2\\y=\frac{44}{8}-2 \\y=\frac{11}{2}-2\\ y=\frac{11-2*2}{2}\\ y=\frac{11-4}{2}\\ y=\frac{7}{2}=3.5

7 0
2 years ago
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