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sveticcg [70]
3 years ago
13

Which of the following inequalities are true

Mathematics
1 answer:
tekilochka [14]3 years ago
4 0

Answer: The answer is E: |-4|<|-7| and C: |-7|>|4|

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Determine LaShawn's average speed in meters per hour
abruzzese [7]
His average speed per minute is 1,448 meters per minute, and there are 60 minutes in a single hour. You would multiply 1,448 by 60 to get the answer of 86,880 meters per hour.
6 0
3 years ago
URGENTS PLLLLLSSSSSSSSS
Arlecino [84]
Just divide 300 by 4 since 25% is 1/4
300/4 = 75
D. 75
Hope this helps!
5 0
4 years ago
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What is the value of 20+30(7+4)+5+2(7+99?
KATRIN_1 [288]

Answer:

the answer is 567

Step-by-step explanation:

20+30(11)+5+2(106)

20+330+5+212

= 567

5 0
3 years ago
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What is true regarding two adjacent arcs created by two<br> intersecting diameters?
Juli2301 [7.4K]

Given:

Two diameters intersect each other.

To find:

The correct statement regarding two adjacent arcs created by two  intersecting diameters.

Solution:

We know that, two diameter intersect each other at origin and measure of arc is equal to the corresponding angle generated by the intersection of diameters.

If two lines intersect each other then we get 4 angles and sum of any two adjacent angles is 180°.

It means the sum of any two adjacent central angles generated by the intersection of diameters is 180°.

So, the sum of two adjacent arcs created by two  intersecting diameters is 180°.

Therefore, the correct option is C.

7 0
3 years ago
Find the area of the shape shown below.​
Tamiku [17]

Answer:

28 square units.

Step-by-step explanation:

Let us divide the shape into two rectangles and a right triangle. The resulting composite figure is attached.

As we see in the figure the area A_T of the triangle is

A_T= \frac{1}{2} (2)(4)=4\: units^2.

The area A_{r1} of the bigger rectangle is (it's actually a square )

A_{r1}=4*4=16\:units^2,

and the area of the smaller rectangle is

4*2 =8\:units^2.

Therefore, the total area A_{tot} of the shape is

A_{tot}= A_T+A_{r1}+A_{r2}

A_{tot}= 4\:units^2+16\:units^2+8\:units^2

\boxed{A_{tot}=28 \:units^2}

5 0
3 years ago
Read 2 more answers
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