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sveticcg [70]
3 years ago
13

Which of the following inequalities are true

Mathematics
1 answer:
tekilochka [14]3 years ago
4 0

Answer: The answer is E: |-4|<|-7| and C: |-7|>|4|

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Find the fifth term in the geometric
OlgaM077 [116]

Answer:

<h2>          a₅ = 162</h2>

Step-by-step explanation:

The nth term in the geometric sequence:  a_n=a_1\cdt r^{n-1}

a₁ = 2  and  r = 3

So:

    a_5=a_1\cdot r^4=2\cdot3^4 = 2\cdot81=162

8 0
3 years ago
Twice a number (z) added to 21 is equal to 9 times the number added to 7. What is the number?
pickupchik [31]

Answer:

The number is  2

Step-by-step explanation:

Twice a number (z) = 2*z = 2z

Twice a number (z) added to 21  = 2z + 21

9 times the number added to 7 = 9z + 7

9z + 7 = 2z + 21

Subtract 2z form both sides

9z - 2z + 7 = 21

       7z + 7 = 21

Subtract 7 from both sides

7z = 21 - 7

 7z = 14

Divide both sides by 7

z = 14/7

z = 2

5 0
3 years ago
If z = 3cis30°, z3 in rectangular form is _____ +_____ i.
oee [108]
The rectangular form is 3c/30=z
Z=10 3c//30
10z+70x + 17x-10z
6 0
3 years ago
Write a quadratic equation ax²+ bx + C = 0, whose coefficients are a =-9, b = 0, c = -2
aksik [14]
<h3>ax² + bx + c = 0</h3>

<em>Let's write -9 where we see A</em><em>:</em>

<h3>-9x² + bx + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>

<h3>-9x² + 0.x + c = 0</h3>

<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>

<h3>-9x² + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>

<h3>-9x² + -2 = 0</h3>

<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>

<em>Let's put the known and the unknown on different sides:</em>

<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>

<h3>-9x² = 2</h3>

<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<h3>x² = 2/-9</h3>

<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>

<em>Please do not report</em><em>:</em><em>(</em>

<em>I hope I got it right, I'm trying to improve my English a little :)</em>

<h3><em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>

<h3><em><u>#XBadeX</u></em></h3>
8 0
3 years ago
Is 4000000 mililimeters equal to 4 kilometers?
user100 [1]
Yes it is 4 billion milimeters is 4 kilometers


6 0
3 years ago
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