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weeeeeb [17]
2 years ago
5

there was a total of $548 collected for the school play. the adult tickets cost $6 and the student tickets cost $4. if 12 more s

tudent tickets were sold than adult tickets, find the number of adult and student tickets sold.
Mathematics
2 answers:
balandron [24]2 years ago
7 0
You can first make the equations:

6x+4y=548
y-12=x

Here, you can use the substitution method and you get:

6(y-12)+4y=548
6y-72+4y=548
10y=620
y=62

Then there are 62 student tickets and 50 adult tickets.

Sonbull [250]2 years ago
3 0

Answer: There are 50 adult tickets and 62 student tickets.

Step-by-step explanation:

Since we have given that

Cost of adult ticket = $ 6

Cost of student ticket = $ 4

Total cost = $ 548

Number of adult ticket be 'x'.

Number of student ticket be 'x+12'

According to question, we get that,

6x+4(x+12)= 548

6x+4x+48 = 548

10x = 548-48

10 x = 500

x = 500 ÷ 10

x = 50

x + 12 = 50 + 12 = 62

Hence, there are 50 adult tickets and 62 student tickets.

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14 is 70% of 20.
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3 years ago
What is the GCF of 48m5n and 81m2n2
Art [367]
48m^5n: 3*2^4*m^5n

81m^2n^2: 3^4m^2n^2

GCF: 3*m^2n
8 0
3 years ago
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
Adrian belter hit 48 home run during the 2004 major league baseball season, but only hit 19 home runs in 2005 season. By what pe
Alex777 [14]
Difference = 48-19
= 29
production decrease = 29 × 100/ 48
= 60.41%
5 0
2 years ago
-(-8n+3.9)
nataly862011 [7]

Answer:

8n - 3.9

Step-by-step explanation:

Given

- (- 8n + 3.9 ) ← multiply each term in the parenthesis by - 1

= 8n - 3.9

4 0
3 years ago
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