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kompoz [17]
4 years ago
6

For problems 1 and 2, determine if the given coordinate pair is a solution to the system of inequalities.

Mathematics
1 answer:
Ede4ka [16]4 years ago
4 0
Not sure because I’m doing that same thing
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SOMEONE PLEASE HELP MEE
melomori [17]

Answer:

The missing numbers are 12 and 39 respectively

Step-by-step explanation:

From the table, we can see that the ratio of the left column to the right is 3/5

So at any point in time, the values on a particular row of the table must conform

to this ratio

In other light, we have to multiply what we have on the left by 5/3 to get what’s on the right

and we have to multiply what we have on the right by 3/5 to get what’s on the left

We have this as follows;

20 * 3/5 = 12

and;

65 * 3/5 = 39

6 0
3 years ago
Evaluate the expression??<br> -5/k+1 for k =-1
vladimir2022 [97]

Answer:

undefined

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Define

-5/(k + 1)

k = -1

Step 2: Substitute and Evaluate

-5/(-1 + 1)

-5/0

undefined (we cannot divide anything by 0)

8 0
4 years ago
1. If u were to draw a tree diagram showing all the possible outcomes for rolling a six sided die twice, how many total outcomes
Furkat [3]
1. 2). 2. 1) 3 * 2 =6
8 0
3 years ago
Roberto is dividing his baseball cards equally between himself, his brother, and his 3 friends. Roberto was left with 9 cards. H
Eduardwww [97]

Answer:

The answer would be 45.

Step-by-step explanation:

5*9=45

8 0
3 years ago
Read 2 more answers
At the start of the school year, students in Mr. Pi’s class were asked the
kupik [55]

Answer:

  • <u><em>No, there is not enough information to determine how many students were absent that particular morning.</em></u>

Explanation:

<em>The probability of randomly selecting a student who answered the question “yes”</em> is the number of students that responded yes divided by the number of students present. Thus, it was:

  • <em>21/30 = 7/10</em>

The probability of randomly selecting a student who answered the question “no” is the number of students who answered "no" divided by the number of students present. Thus, it was:

  • <em>9/30 = 3/10</em>

<em>On one particular morning later in the year, the probability of randomly selecting a student who had answered the question “yes” was 3/4</em>

The equivalent ratios to 3/4 will tell you the possible combinations of students that answered yes and students present on that particular morning.

For instance: 3/4 = 6/8

  • 6/8 would mean that there were 6 students that answered yes and 8 total students on that particular morning.

Since more than half of class was present, the total number of students was greater than 15. Then, you must find a ratio with a denominator greater than 15 (and less than 30).

The other equivalent ratios to 3/4 are: 9/12, 12/16, 15/20, 18/24, 21/28, 24/32, ...

That means that the only possibilities with more than 15 and less than 30 present students are 12/16, 15/20, 18/24, and 21/28.

The total number of absents might have been:

  • 30 - 28 = 2
  • 30 - 24 = 6
  • 30 - 20 = 10
  • 30 - 16 = 14

Since at least one of the students who had answered “yes” was absent and at least one of the students who had answered “no” was absent, all the above possibilities are valid: <em>there is not enough information to determine how many students were absent that particular morning; </em>they could be 2, 6, 10, or 14.

7 0
3 years ago
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