Answer:
There were total 4 samples collected and each sample had a sample size of n = 100.
Step-by-step explanation:
We are given the following information in the question:
Collection of samples:




Hence, there were total 4 samples collected and each sample had a sample size of n = 100.
Answer:
Step-by-step explanation:
butt
Answer:
hello your question lacks the required options but i will provide a general answer to your question
answer : The mean value and the standard deviation would allow us use a Z-score
Step-by-step explanation:
mean value = 231 minutes
standard deviation ( std ) = 40 minutes
sample size = 40
The parameters that would be applicable while use Z-score are : The given mean value and the standard deviation
This is because the value of a z-score gives us an information on how far we are from the mean score i.e. number of standard deviations
+Zscore means that the score is above the average value
-Zscore means that the score is below the average value
Answer:
Step-by-step explanation:
Was it
Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.