Answer:

Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin)
.
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is

The square root of 75000 is 273.86
The answer is
4.0000000000006667
Answer: The correct option is (D) 196608.
Step-by-step explanation: We are given to find the value of the 9th term in the following geometric sequence :
3, 12, 48, 192, . . .
We know that
the n-th term of a geometric sequence with first term a and common ratio r is given by

For the given sequence, we have
first term, a = 3 and the common ratio, r is given by

Therefore, the 9th term of the given sequence will be

Thus, the required 9th term of the given sequence is 196608.
Option (D) is CORRECT.
I would say b the reason is because -2 is on the x and -6 in on the y so it would be left then down.