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Umnica [9.8K]
3 years ago
9

Factorise x2 + 13x + 42

Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

you can use the formula "<em>Cross method" </em>  in which the last number of the equation is the sum of 2 number multiplication that also sums the 2nd num of the equation.

so it becomes

(x +6)(x +7)

WHY?

Bcs when u multiply 6 x 7 = 42 ( the last number of the equation)

      when u sum 6 + 7 = 13 ( the 2nd number of the equation)

Hope this helps :)

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3 years ago
Urgent ;<br>if a^3+b^3=11 and a^3-b^3=5, evaluate a^6-b^6
11111nata11111 [884]

Factorize using the difference of squares identity.

a^6 - b^6 = \left(a^3\right)^2 - \left(b^3\right)^2 = \left(a^3 - b^3\right) \left(a^3 + b^3\right)

Then

a^6 - b^6 = 11 \cdot 5 = \boxed{55}

5 0
1 year ago
Todd’s average score for six tests was 92. If the sum of the scores of two of her tests was 188, then what was her average score
natita [175]

Answer:

91

Step-by-step explanation:

Todd’s average score for six tests = 92.

The sum of two of her test = 188

First, we need to find the total score for the six test. This given below:

Average = sum of all test / number of test

sum of all the test = average x number of test

average score for six tests = 92.

Number of test = 6

Sum of all the Tests = 92 x 6 = 552

Sum of four test = sum of all the test — sum of two test

Sum of four test = 552 — 188 = 364

Now we can solve for the average of the other four test as shown below:

Average of four test = 364/4= 91

3 0
2 years ago
Read 2 more answers
4, 02, 03, α4, 28.<br> Find the common difference
hram777 [196]

Answer:

1

Step-by-step explanation:

GCF

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3 years ago
Use your equation from Exercise 6 to find m when n=40
Andreyy89

Answer:

=4/5(N+7)N

Step-by-Step Explanation:

We move all terms to the left:

-(4/5(N+7)N)=0

Domain of the equation: 5(N+7)N)!=0

N∈R

We multiply all the terms by the denominator

-(4=0

We add all the numbers together, and all the variables

=0

N=0/1

N=0

5 0
2 years ago
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