Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius
to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=

points (-3,2) and (1,5)
D=

D=

D=

D=

D=5
center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1
the point (-7,5) and (7,-1) lie on this circle
radius=5 units
the points (-7,5) and (-7,1) lie on this circle
First plug in (x+h) for x in the function.
f(x+h)= 2(x-h)^2-3(x-h) = 2(x^2-2xh+h^2)-3x-3h =
2x^2-4xh+2h^2-3x-3h - 2x^2 +3x =
(-4xh +2h^2-3h)/h
-4x +2h-3
Answer:
4
Step-by-step explanation:
The one that weighs the less is 80
<u><em>Pls give brainlest.</em></u>
You have to solve the two equations by eliminating x or y
<span>2x+5y=10 </span>
<span>x-3y=1 </span>
<span>Multiply all terms of second equation by two and subtract from first equation, thus eliminating x </span>
<span>2x+5y-2x+6y=10-2 </span>
<span>11y=8 </span>
<span>y=8/11 </span>
<span>x=3y+1=3* 8/11+1=25/11 </span>
<span>11x+11y= 11*25/11+ 11*8/11 </span>
<span>= 25+8=33</span>